When Do You Hear Minimum Sound Intensity While Walking Away from Speakers?

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The discussion focuses on determining the distances from a loudspeaker where minimum sound intensity occurs due to destructive interference while walking away from the speaker. The speaker setup involves two speakers 3 meters apart, emitting a 686 Hz tone in phase, with the speed of sound at 343 m/s. The wavelength is calculated to be 0.5 meters, and the user attempts to find the path length difference using the Pythagorean Theorem. However, it's noted that the initial path length difference must be considered, and destructive interference can occur at multiple intervals beyond just λ/2. The approach is generally correct but requires careful consideration of these factors for accurate results.
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Homework Statement


You are standing 2.5m directly in front of one of two loudspeakers. they are 3m apart and both are playing a 686hz tone in phase. As you begin to walk directly away from the speaker, at what distances from the speaker do you hear a minimum sound intensity? Assume speed of sound of 343m/s


Homework Equations





The Attempt at a Solution



I've been trying to approach the problem using the idea that the minimum sound intensity will occur where the waves experience destructive interference, which will happen when they are a half-wavelength apart in phase.

so the wavelength can be calculated at .5m,

So r = phase difference.

r = wavelength*.5

r=(.5)*(.5m)

then, by the Pythagorean Theorem. r = (15.25 + 5x + 5x^2)^.5 -(2.5 + x)

where x is the distance from the starting point.


Is this the correct approach to take?
 
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You have the basic idea, but you need to be a bit more careful and check some of your assumptions. For example, when x=0, there's already a path length difference that you need to account for. Destructive interference can happen not only when the difference is λ/2, but when it's 3λ/2, 5λ/2, and so on.
 
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