roshan2004
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In what conditions do we use time dependent and time independent Schrodinger's wave equations?
Gerenuk said:The time-dependent version is always the right choice.
However if your potential does not depend on time, but position only V(x) (unlike V(x,t)), then you can use the trial solution \psi(x,t)=\phi(x)e^{-i E t/\hbar} and derive an equation for the special part \phi of the wavefunction. You effectively get the time-independent version of the Schrödinger equation. From this time-indepedent special case you can first find \phi and E and finally put it back into the full wavefunction \psi(x,t). Please try that above exercise with the trial solution.
<br /> <br /> Read my first sentence again .. you said it is *always* best to use the TDSE. I said it is best to use the TISE when solving a time independent potential. <br /> <br /> To answer your question, yes, I would also tend to use the TISE first in cases where it is appropriate to treat the time-variant part of the potential as a (weak) perturbation.<br /> <br /> In cases where there is truly a strongly-coupled time-dependent potential to deal with, I would probably not use either form of the Schrodinger equation, but instead I would formulate solutions in the interaction picture, where quantum propagators are used to describe the time-evolution of some initial state, which I would represent as a linear combination of eigenstates. Of course that choice is largely due to my own education and training, and the sorts of problems I run into in my research. Honestly, outside of fairly straightforward derivations and pedagogic illustrations, I have found little use for the TDSE.<br /> <br /> I understand that others will have a different take .. I was just providing a counter-example to your statement that, "The time-dependent version is always the right choice."Gerenuk said:It's not a matter of taste. What you want to use merely depends on whether your potential is V(x,t) or V(x)[/tex]. What time-independent eigenstates do you want to find if you haven't even given a time-independent potential to deal with?<br /> <br /> Maybe you are referring to some perturbation theory approximations?
I wanted to emphasize that there is only one equation that describes the physics. Everything else is a special case. This is to prevent misconceptions about "dualities" and "special cases".SpectraCat said:I understand that others will have a different take .. I was just providing a counter-example to your statement that, "The time-dependent version is always the right choice."
roshan2004 said:In what conditions do we use time dependent and time independent Schrodinger's wave equations?