When Should the Violinist Play Her Note? Understanding Timing in an Orchestra

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To synchronize the sound from the violinist and drummer for a listener in front of the conductor, the violinist should wait approximately 0.1 seconds after the drummer plays, accounting for the sound delay. The speed of sound is about 330 m/s, which determines this delay over the 33 meters distance to the listener. The time it takes for light to travel that same distance is negligible compared to the sound delay, effectively rounding to zero. Thus, the assumption that both players see the conductor's command simultaneously holds true due to the significantly faster speed of light. Overall, the problem emphasizes the importance of understanding sound and light travel times in orchestral timing.
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Homework Statement


An orchestra wants to have a listener in front of a conductor hear notes at the same time, played by the violinist located next to the conductor and from a drummer located 33m further back.

a) How long should the violinist wait before playing her note? (assuming drummer plays as soon as conductor gives command)

b) Why may one assume that the two players see the conductor command at the same time?

Homework Equations





The Attempt at a Solution



I really have no clue on how to attempt this, I don't know where to start. I really need your guys help please.
 
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sound and light both travel at certain speeds. How long does it take for the light to travel to the drummer from the conductor and how long does it take sound to travel to the conductor from the drummer?
 
Would I use the equation speed of light=(frequency)(wavelength) and then solve for frequency? Speed of light = 3x108 and wavelength = 33m?
 
No. What is the basic relationship between time spent traveling, speed, and distance traveled?
 
speed = distance / time
normal / average speed of sound in air is taken as 330 m / s

330 = 33 / t

t = 33 / 330 = 0.1 seconds.

Did you mean anything like this ?
 
Frequency?
 
physics(L)10 said:
Frequency?

No. Even though it's against the rules to do peoples' homework, look at the post above you. This problem has nothing to do with frequency.

You can think of light and sound both traveling in a straight beam at a constant speed. The problem basically asks you to calculate how long it takes that beam of sound to travel from the drummer to the listener. If there is some delay T between the drummer playing and the listener hearing whereas the delay is 0 for the violinist playing and the listener hearing, to synchronize the music, you'd make the violinist wait time T and then start playing. Does that make sense?

Also, when you do the same calculation for T but with light (the time it takes for the beam of light to travel from the conductor to the drummer, representing the delay between the "go" signal and when the drummer sees it), you will find it is extraordinarily tiny and basically rounds to zero when added to the delay caused by sound. Therefore, its contribution is irrelevant compared to the delay caused by sound.
 
So basically it has nothing to do with any wave equations? It`s more of a kinematics question?

So light would be:

3x108=33/t

t=33/3x108

t=1.1x107

So you would just add the two and it would basically be 0.1sec that the violinist should wait since t is so small for light?

b) They see the same players at the same time because the speed of light is so fast compared with sound?
 
physics(L)10 said:
So basically it has nothing to do with any wave equations? It`s more of a kinematics question?

So light would be:

3x108=33/t

t=33/3x108

t=1.1x107

So you would just add the two and it would basically be 0.1sec that the violinist should wait since t is so small for light?

b) They see the same players at the same time because the speed of light is so fast compared with sound?

Yes. For b, I wouldn't say they see the signal at the same time. I'd say the order of magnitude in the visual delay is far less than order of magnitude of the delay caused by sound, so you can ignore it without affecting your answer.
 
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Alright, thanks a lot :D
 
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