When will the velocity vector make an angle of 45 degrees?

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Homework Help Overview

The problem involves determining when a velocity vector, derived from a given position vector, makes an angle of 45 degrees with the horizontal. The position vector is defined as r = bt²i + ct³j, where b and c are positive constants.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to differentiate the position vector to find the velocity vector but expresses confusion about the components of the velocity. A participant suggests considering the ratio of the vertical and horizontal components of the velocity vector when it makes a 45-degree angle.

Discussion Status

Some guidance has been provided regarding the relationship between the components of the velocity vector at a 45-degree angle. The discussion is exploring the implications of this relationship without reaching a consensus on the next steps.

Contextual Notes

The original poster indicates a feeling of confusion and being stuck in their attempts, highlighting the challenge of interpreting the components of the velocity vector.

bharp24
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i have been given that vector r = bt^2i + ct^3j where b and c are positive constants, and i need to know when the velocity vector will make an angle of 45 degrees.

i have been trying to figure it out and am just confused. i have taken the derivative of vec r, because i know that it becomes velocity but i don't know what to do from there. i cannot figure out the components of what makes up the velocity vector. i feel like i am going in circles. please someone help!
 
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Hint: When the velocity vector makes an angle of 45 degrees with respect to the horizontal, what can you say about [itex]V_y/V_x[/itex]?
 
it will = 1 because the sin and cos of 45 degrees are the same...right?
 
Right!
 

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