Where does the energy of gravity come from?

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The discussion centers on the origin of energy in gravitational interactions, particularly during a gravitational slingshot maneuver. Participants debate whether gravity can generate energy and how it affects celestial bodies like the Moon and Earth. It is noted that while gravity is a static force that does not do work in a traditional sense, it can influence the motion of objects, leading to energy transfer. The Moon's orbit is described as being maintained without energy loss, as its acceleration is perpendicular to its motion, thus not changing its kinetic energy. Ultimately, the conversation highlights the complexity of gravitational energy dynamics and the ongoing questions about energy conservation in orbital mechanics.
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Say you were to slingshot around the moon and gain momentum. In so doing you would have gained Energy from gravity. Basically because energy is conserved there has to be some way that the force of gravity "radiating" out from the moon would come in contact with a space shuttle and speed it up. How does this work?
 
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I think that the energy you gained ,come from the "kinetic energy" of the moon!
 
Gravity is a static force. There is no energy expended in static forces. Consider a book sitting on a table. It has a certain potential energy defined by its height, but that energy level never changes, so gravity is not doing any work on it.
 
I don't understand. I don't see how it could speed something up without transferring some kind of energy.
 
Speeding something up is different (I should have read more carefully/been more descriptive), but in order to drop something you first have to lift it. It is conservative, just like a spring. The total energy is the potential energy plus the kinetic energy and it is always constant (if there is no loss from other factors).

A gravitational slingshot, however, does steal orbital energy. It is a bad (confusing) example for examining why there is no energy generation in gravity.
 
Gravity is a force, if everything is static, there's no work and no energy required. But take two celestial bodies, say the Moon and the Earth. Gravity keep them revolving around each other but the Moon would fly off tangentially if it were not for gravity. The Moon's course is constanlty being altered by the Earth's gravitational pull. This is not a static situation, the moon is being accelerated, work is being done and the question is... where does the energy come from?
 
pedridge said:
The Moon's course is constanlty being altered by the Earth's gravitational pull. This is not a static situation, the moon is being accelerated, work is being done and the question is... where does the energy come from?
No.
Work is force * distance. Where is the distance here?
 
Looking at the Moon's trajectory. It is constantly being accelerated towards the Earth. Relative to the Earth there is no movement, but from the Moon's perspective its course is being bent away from its straight line trajectory and therefore work is being done.
Relative to the center of Earth there is no movement, but in rectalinear space the Moon is being constantly accelerated from a constant speed and course, and that is the distance.
Thanks, for your reply, and I'm not tryiing to be argumentative, this puzzles me.
 
  • #10
When your spaceship uses the Moon to slingshot, the Moon slows down a very, very small fraction. That is where the energy comes from.

It is analagous to a skater grabbing the bumper of a passing car and pulling himself forward. The car slows down as the skater speeds up.
 
  • #11
pedridge said:
Looking at the Moon's trajectory. It is constantly being accelerated towards the Earth. Relative to the Earth there is no movement, but from the Moon's perspective its course is being bent away from its straight line trajectory and therefore work is being done. Relative to the center of Earth there is no movement, but in rectalinear space the Moon is being constantly accelerated from a constant speed and course, and that is the distance.
No. The acceleration is always perpendicular to the direction of motion. It causes no change in the kinetic energy of the moon (caveat: elliptical orbits, but they are conservative too). Consider that once a month the moon gets back to where it started, going the same speed as it was a month ago: exactly the same state/energy. Acceleration perpendicular to the direction of motion does not produce a change in speed.
 
  • #12
Hey pedridge,

I think you're onto something. I stumbled upon this thread when I googled the same question you asked.

I agree that gravity introduces energy into the "closed system" of the Universe. Indeed, Newton claimed he was not attempting to explain where gravity came from or what the driving force behind it was.

Physicists just make up terms like "static force" and "potential energy" in order to get around the "matter/energy is neither created nor destroyed." I think it's clear using the thought experiments you propose that matter continuously creates energy in the form of gravitational force from seemingly nothing.
 
  • #13
The moon actually gains energy in its orbit from the rotation of the Earth and the tidal forces the moon exerts on the Earth.

As such, the moon is very slowly moving away from us, and the Earth's rotation is very slowly slowing down.

Over the course of the Earth's history (4.5 billion years), the Earth day has slowed down from ~6 hours to 24 hours, and the moon has drifted something like 4 times further away (don't quote me on these figures).

The point is, energy is not lost, just transferred.
 
  • #14
I can imagine one day the travesty of 'wasting moon energy' as space travel becomes more common. The moons energy is a limited resource!
 
  • #15
WackyDumpsite said:
Hey pedridge,

I think you're onto something. I stumbled upon this thread when I googled the same question you asked.

I agree that gravity introduces energy into the "closed system" of the Universe. Indeed, Newton claimed he was not attempting to explain where gravity came from or what the driving force behind it was.
Newton did NOT say that. He did say he was describing gravity, not explaining it ("non hypothesen fingo"- "I frame no hypotheses") but he certainly never talked about a "driving force" behind gravity. One force does not require another "driving force".

Physicists just make up terms like "static force" and "potential energy" in order to get around the "matter/energy is neither created nor destroyed." I think it's clear using the thought experiments you propose that matter continuously creates energy in the form of gravitational force from seemingly nothing.
Yes, in a sense the different kinds of energy are a "bookkeeping" device but very useful ones. Physicists do not "just make up" such terms any more than accountants "just make up" the numbers they put in the books. Matter does not "create" energy from "seemingly nothing". All that the thought experiments baseplayer142 proposes show is that he (and you) do not understand the physics involved. He, at least, asked for assistance. You just tell him to ignore physicists who "just make up" things!
 
  • #16
I'll restate the problem I'm having.
Take any two obvious large objects as an example, the two easiest are the Earth and the Moon, locked in an orbit around each other, by gravity. Simple. The question becomes... as the Moon is not being allowed to take off on a tangential course, it is being constantly being accelerated towards the Earth. Simple, again. The energy required must be supplied from somewhere, and the question is where?
Mass and energy are two sides of the same thing, as there is no other source for the energy required, matter has to be converted to energy, but where is the loss of mass?
 
  • #17
The answer is...there is no energy required for a circular orbit to remain stable. That's the whole point people have been trying to tell you, but you seem to ignore.

Remember P=F dot V

Where P is the power (energy per second) radiated, F is the force, and V is the velocity.

For a circular orbit, F and V are always perpendicular (elliptical orbits also don't radiate power, but it's more complicated). Therefore, F dot V is zero and there is no power radiated!
 
  • #18
Matterwave said:
The answer is...there is no energy required for a circular orbit to remain stable. That's the whole point people have been trying to tell you, but you seem to ignore.

And that makes no sense which is what we've been trying to tell you. Your equations don't help explain how the Sun is able to keep the Earth moving in a circular manner as opposed to flying straight. Or the Earth and the Moon, etc. To say that no energy is needed to maintain a circular orbit is nonsensical. It obviously requires energy.

Take a table. If I kick the bottom of the table, in outer space it will move in the direction it was kicked. But Earth's gravity is continuously pulling it downward. This is work being done. Work requires energy. There is no matter --> energy conversion that explains this as far as I know, and petridge pointed this out as well. So where does it come from?

I've raised this issue up in a conversation with a Stanford PhD physics professor about this. She didn't know how to answer it and said things like 'we don't know much about gravity' and 'we have this concept of potential energy.' If you have better credentials than that, by all means give a real answer, don't just refer to some equation as proof that you don't need to account for it.
 
  • #19
HallsofIvy said:
Newton did NOT say that. He did say he was describing gravity, not explaining it ("non hypothesen fingo"- "I frame no hypotheses") but he certainly never talked about a "driving force" behind gravity. One force does not require another "driving force".

I apologize for getting the quote wrong, or even the subtleties of what he said. But how is "describing it, not explaining it" NOT the same as saying he was saying how it works, not where it comes from? Where what comes from? The energy that gravity is clearing introducing into the system.
 
  • #20
WackyDumpsite said:
I apologize for getting the quote wrong, or even the subtleties of what he said. But how is "describing it, not explaining it" NOT the same as saying he was saying how it works, not where it comes from?
Objects fall at 9.8m/s^2. That is describing it without explaining it. It says nothing about how or why objects fall at that rate.
 
  • #21
WackyDumpsite said:
And that makes no sense which is what we've been trying to tell you. Your equations don't help explain how the Sun is able to keep the Earth moving in a circular manner as opposed to flying straight. Or the Earth and the Moon, etc. To say that no energy is needed to maintain a circular orbit is nonsensical. It obviously requires energy.

Take a table. If I kick the bottom of the table, in outer space it will move in the direction it was kicked. But Earth's gravity is continuously pulling it downward. This is work being done. Work requires energy. There is no matter --> energy conversion that explains this as far as I know, and petridge pointed this out as well. So where does it come from?

I've raised this issue up in a conversation with a Stanford PhD physics professor about this. She didn't know how to answer it and said things like 'we don't know much about gravity' and 'we have this concept of potential energy.' If you have better credentials than that, by all means give a real answer, don't just refer to some equation as proof that you don't need to account for it.

Perhaps, it would be easier to ask you where do you think the energy goes?

Energy is transferred, not destroyed. So, if it takes Energy to keep the moon in orbit, where is this energy going?
 
  • #22
Matterwave said:
Perhaps, it would be easier to ask you where do you think the energy goes?

Energy is transferred, not destroyed. So, if it takes Energy to keep the moon in orbit, where is this energy going?

I don't know. Perhaps it dissipates as heat. Where is the energy transferred when the tides move back and forth because of the Moon's gravitational pull?
 
  • #23
Some of that energy is dissipated as heat because there is friction between the oceans and the Earth. Some of that energy is transferred to the moon, which makes it orbit larger as time goes on. (As I mentioned in a previous post)

But there are no frictional forces in the Earth/moon system (to first approximation anyways), so why would energy be dissipating as heat?
 
  • #24
Matterwave said:
Some of that energy is dissipated as heat because there is friction between the oceans and the Earth. Some of that energy is transferred to the moon, which makes it orbit larger as time goes on. (As I mentioned in a previous post)

But there are no frictional forces in the Earth/moon system (to first approximation anyways), so why would energy be dissipating as heat?

Aha! So you'll concede that there is energy dissipated as heat in the wave/Moon system. Therefore, there is energy coming from somewhere. This is gravitational energy.
 
  • #25
Were we talking about the wave/Moon system? I thought we were talking about keeping the Moon in it's orbit.

The energy from the wave/Moon system comes from the rotation of the Earth (Hence, why the Earth's rotation is slowing down). It's the rotational kinetic energy.
 
  • #26
pedridge said:
The energy required must be supplied from somewhere, and the question is where?
What energy?

Caveat: The Moon is slowly receding from the Earth due to tidal interactions (very slowly; 3.8 cm/yr currently) and the Earth-Moon system is losing a *tiny* bit of energy in the form of gravity waves.

These changes are extremely tiny in comparison to the Moon's orbital energy. Ignoring those tiny effects, there is *no* change in energy as the Moon orbits the Earth.

I'll start with a circular orbit. The gravitational potential energy is obviously constant in a circular orbit. While the velocity vector is constantly changing direction in a circular orbit, the magnitude of the velocity vector does not change. As kinetic energy is 1/2mv2, kinetic energy is also constant in a circular orbit. For a non-circular orbit, gravitational and kinetic energy do change over the course of an orbit, but the sum of gravitational and kinetic energy remains constant. There is no change in energy as two objects orbit one another.
 
  • #28
i don't know
 
  • #29
Classical Physics relates to the observable universe. We are aware of gravity's grip and we observe its interaction with our universe. However, we do not know how gravity operates. While we can accurately define gravity's observable effects, we do not understand the nature of gravity.

Think about it. This is a fundamental force that works throughout the universe. Yet, we are unable to describe what or how this is being done. It may be that we are unable to understand gravity. Since we spend our entire life in its grasp, perhaps we are restricted from seeing it for what it is. I do not care to believe this.

Gravity may be a separate form of energy or it may be a part of the energy we already know. The only thing we truly must face is that we do not know what it is. Only by accepting that fact will we begin to believe there are other ideas of what gravity is and what it can do.

Gravity is the only force that we are unable to shield, direct, create, or destroy (use up as in transfer). Gravity is a perpetual force that can be found everywhere and if we could understand anything about it, we would never need another source of energy.

Wow, don’t believe this? OK, consider this, if we could diminish or increase gravity’s effects in a prescribed area, we could create an unequal gravity field. If we could place one side of a balanced flywheel in the field, the flywheel would become unbalance and would begin to turn. One side of the flywheel is actually falling through the heavier side of the gravity field. While the field remains stable, the flywheel will continue to turn as its edge enters the unequaled gravity field. This means that a knowledge of gravity could, at the least, provide us with a constant, unrelenting source of energy anywhere on this planet. And that is only if we knew how to increase or decrease gravity in one small area.

Isn’t this enough encouragement for us to put everything we can into discovering what gravity really is and not just what it does?
 
  • #30
The moon moves when an object slingshots around it. Gravity is not a force, it is the curvature of space due to matter.
 
  • #31
How about this. We have two steel balls attached to each other with a wire. They are spinning around each other in empty space. No gravity involved. The force that causes the acceleration comes from the tension in the wire. The force of the wire of ball1 is equal and opposite the force on ball2. There is no net force.

If you believe the acceleration is doing work then after some time we should see some effect of that work. But nothing changes the temperatures remain the same. The velocities remain the same. So where is the energy going? Work = force (dot product) distance. In this case force and distance are perpendicular so the (dot product) is zero.
 
  • #32
Chronos said:
The moon moves when an object slingshots around it. Gravity is not a force, it is the curvature of space due to matter.



This is a great demonstration of the effects of gravity; however, it does not explain how gravity does what it does.

As to the question of whether gravity is a force, step off the fifth floor of a building at sea level on planet Earth and tell me if there is not a force at play. For that matter, help a buddy move his stuff into an upstairs apartment and tell me what you are fighting as you climb the stairs with his futon.

The real answer is not a definition of what gravity does, but an explanation of how gravity does it. Conquering gravity would liberate the human race.
 
  • #33
edpell said:
How about this. We have two steel balls attached to each other with a wire. They are spinning around each other in empty space. No gravity involved. The force that causes the acceleration comes from the tension in the wire. The force of the wire of ball1 is equal and opposite the force on ball2. There is no net force.

If you believe the acceleration is doing work then after some time we should see some effect of that work. But nothing changes the temperatures remain the same. The velocities remain the same. So where is the energy going? Work = force (dot product) distance. In this case force and distance are perpendicular so the (dot product) is zero.




Ok, there is no gravity (perceptible gravity) at play, so why is this part of the discussion?

It is a good thought experiment, but the true energy in this example was applied at the beginning when the balls were originally flung in the “orbit” you have created. They will eventually slow down as effects from other objects play on them, but, aside from the centrifugal force that would separate the two if the wire were cut, there appears to be no other forces at play. What am I missing?
 
  • #34
Don Hicks said:
Ok, there is no gravity (perceptible gravity) at play, so why is this part of the discussion?

It is a good thought experiment, but the true energy in this example was applied at the beginning when the balls were originally flung in the “orbit” you have created. They will eventually slow down as effects from other objects play on them, but, aside from the centrifugal force that would separate the two if the wire were cut, there appears to be no other forces at play. What am I missing?

That's why he's bringing it up. Same arrangement, different cause. It makes it easier to show why gravity is doing more work since it's easy to see that the connecting wire is doing no work.
 
  • #35
Don Hicks said:
They will eventually slow down as effects from other objects play on them

Newton's first law is still good "objects in motion will stay in motion". There is no friction they just keep going and going...
 
  • #36
edpell said:
Newton's first law is still good "objects in motion will stay in motion". There is no friction they just keep going and going...
Not friction - tidal forces. The objects will eventually stop their rotation with their long axis aligned with the closest gravity well.
 
  • #37
I had a similar question that I couldn't answer, and here might be the perfect place to answer it.

Let's say you had a huge stationary object in space, like...a solid ball the size of the solar system, just to go over the top. It has gravity, obviously, due to its ridiculous mass. Then you throw something towards it with a certain amount of force. As it gets closer, the object should start to accelerate due to the gravity of the giant object, right?

So the question is: where is that increase in kinetic energy coming from? It can't just appear out of nowhere, can it? But it's also not stealing any mass or gravity or anything from the giant ball.
 
  • #38
At the start the small ball has potential energy. As it moves faster and faster the potential energy is converted to kinetic energy. The potential energy is stored in the field. The gravity field. Just like a spring. But a spring that is distributed over near by space and has no material substance but does have tension/compression.
 
  • #39
edpell said:
At the start the small ball has potential energy. As it moves faster and faster the potential energy is converted to kinetic energy. The potential energy is stored in the field. The gravity field. Just like a spring. But a spring that is distributed over near by space and has no material substance but does have tension/compression.

Hm, I see. Is that potential energy in the gravity field of the moving object, the giant ball, or both?

This leads me to another question. Let's say you had an impossible bottomless pit, with a constant gravitational pull all the way down and no end. Also no air, so no terminal velocity to interfere with this. If you dropped something into this pit, would it eventually hit a point where it stops accelerating, when all of this potential energy has become kinetic energy? In short: is there a limit to how much a gravitational pull can accelerate a particular object?

I know the situation is impossible, but I'm just trying to visualize how this potential energy in the gravity fields works.
 
  • #40
Bussani said:
Hm, I see. Is that potential energy in the gravity field of the moving object, the giant ball, or both?

This leads me to another question. Let's say you had an impossible bottomless pit, with a constant gravitational pull all the way down and no end. Also no air, so no terminal velocity to interfere with this. If you dropped something into this pit, would it eventually hit a point where it stops accelerating, when all of this potential energy has become kinetic energy? In short: is there a limit to how much a gravitational pull can accelerate a particular object?

I know the situation is impossible, but I'm just trying to visualize how this potential energy in the gravity fields works.
It's not impossible. Not in space. An object can fall from infinity toward another object.

No, the object need never stop accelerating.

Until the two objects are actually touching, there is always some potential energy.
 
  • #41
Ahh, I see. Thanks a lot for the reply.
 
  • #42
pedridge said:
I'll restate the problem I'm having.
Take any two obvious large objects as an example, the two easiest are the Earth and the Moon, locked in an orbit around each other, by gravity. Simple. The question becomes... as the Moon is not being allowed to take off on a tangential course, it is being constantly being accelerated towards the Earth. Simple, again. The energy required must be supplied from somewhere, and the question is where?
Mass and energy are two sides of the same thing, as there is no other source for the energy required, matter has to be converted to energy, but where is the loss of mass?

Answer: Gravitational Potientual Energy

Energy is an extremely useful book keeping system. Yes energy/work is needed to apply a force or vice versa. However physicists note that there are Four Fundemental Forces of nature- essentially by default these Fundamental forces have ability to do work. This ability comes from the property of an object, which can include mass (gravity), charge (coloumb)... etc etc The list goes on.
 
  • #43
Bussani said:
Hm, I see. Is that potential energy in the gravity field of the moving object, the giant ball, or both?

This leads me to another question. Let's say you had an impossible bottomless pit, with a constant gravitational pull all the way down and no end. Also no air, so no terminal velocity to interfere with this. If you dropped something into this pit, would it eventually hit a point where it stops accelerating, when all of this potential energy has become kinetic energy? In short: is there a limit to how much a gravitational pull can accelerate a particular object?

I know the situation is impossible, but I'm just trying to visualize how this potential energy in the gravity fields works.

To answer the first part mostly the small ball falls to the large ball but the large ball does fall a little towards the small ball. So I would say the net motion is due mostly to energy from the field of the large ball and a little from the field of the small ball. It might be correct to say that the motion of the small ball is due 100% to the field of the large ball and the motion of the large ball is due 100% to the field of the small ball, but I would have to think carefully about that.

Since the pit is infinite the initial potential energy is infinite so no problem it keeps gaining energy. But as to the question how much velocity does it gain per unit time (in the shafts inertia frame of reference)? I would say once it gets to say (1-10^30)c the gain in velocity per unit time (as stated above) is very small (but never zero).
 
  • #44
Livethefire said:
Answer: Gravitational Potientual Energy

Energy is an extremely useful book keeping system. Yes energy/work is needed to apply a force or vice versa. However physicists note that there are Four Fundemental Forces of nature- essentially by default these Fundamental forces have ability to do work. This ability comes from the property of an object, which can include mass (gravity), charge (coloumb)... etc etc The list goes on.

No work is done. The definition of work is force (dot product) distance. In this case since the force is always orthogonal to the distance the dot product is always zero.

How are you defining work?
 
  • #45
edpell said:
No work is done. The definition of work is force (dot product) distance. In this case since the force is always orthogonal to the distance the dot product is always zero.

How are you defining work?

Well, I was kind of answering my own question.
I wasn't focusing on the concept of the orbit, rather just the aspect that two masses will attract due to a force.

I realize what your getting at , and it was my inability to really focus on the question. Sorry.
 
  • #46
Could this energy of gravity involve somehow dark matter/energy ?
 
  • #47
WackyDumpsite said:
And that makes no sense which is what we've been trying to tell you. Your equations don't help explain how the Sun is able to keep the Earth moving in a circular manner as opposed to flying straight. Or the Earth and the Moon, etc. To say that no energy is needed to maintain a circular orbit is nonsensical. It obviously requires energy.

Take a table. If I kick the bottom of the table, in outer space it will move in the direction it was kicked. But Earth's gravity is continuously pulling it downward. This is work being done. Work requires energy. There is no matter --> energy conversion that explains this as far as I know, and petridge pointed this out as well. So where does it come from?

I've raised this issue up in a conversation with a Stanford PhD physics professor about this. She didn't know how to answer it and said things like 'we don't know much about gravity' and 'we have this concept of potential energy.' If you have better credentials than that, by all means give a real answer, don't just refer to some equation as proof that you don't need to account for it.

Think of the simple case where the difference in mass between the two bodies is so great that the effect of the smaller mass, m, on the greater, M, can be ignored. Let's suppose mass m is in a circular orbit around M.

By definition of potential energy (and taking our "zero of potential energy" as infinity),

U = - \int_{r}^{\infty} \textbf{F} \cdot \textup{d}\textbf{r} = \frac{-GMm}{r},

where U is potential energy due to gravity, F gravitational force, M the greater mass, m the smaller mass, dr an infinitesimal change in the position of m (the position considered as a position vector, r, extending from the centre of mass of the system, here effectively the centre of mass of M, to the centre of mass of m), r the magnitude (length) of this position vector r, G the gravitational constant (which relates the units). In other words, the potential energy of the satellite m is the work that would be done by the force of gravity if it was to move m from infinitely far away to its current position.

By definition of kinetic energy,

T = \frac{1}{2}mv^2,

where T is the kinetic energy of the orbiting body with mass m, and v its speed, defined as the magnitude of its velocity with respect to the more massive body.

By definition of circular motion,

\frac{\mathrm{d} r}{\mathrm{d} t} = 0

at all points in the orbit. This just means that the distance of the satellite from the more massive body doesn't vary over time.

Less obviously,

\frac{\mathrm{d} v}{\mathrm{d} t} = 0.

That is, the speed of the satellite is constant over time. This follows from Kepler's 2nd law in the special case of a circular orbit; the radius of the orbit doesn't change, so the only way that an equal area can be swept out over an equal time is if the speed is constant.

http://en.wikipedia.org/wiki/Kepler's_laws_of_planetary_motion#Second_law

Therefore

\frac{\mathrm{d} }{\mathrm{d} t} \left(T + U) = 0.

Kinetic energy is constant, and potential energy is constant, so their sum is constant.
 
  • #48
I saw this thread when I was looking for "is gravity energy?"
A conclusion I had come to on my own.
I believe gravity is just energy, specifically kinetic energy.
 
  • #49
I have been thinking about two different possibilities. For one thing, isn't it possible our understanding of energy is incomplete? I mean we say all this stuff about how there must be conservation of energy and all these equations that show this and that, but aren't those all just "proven" by real-life examples we've all seen? I mean to say that we might not be able to answer this question because there is not a good enough understanding of energy.
Also, Einstein's idea that matter warps space-time meant to show that yes, when space is flat and good and all, an object will continue to move in a straight line. However, when space is curved (as it supposedly is around planets), the path of least resistance so to speak is a curved one. Forgive me if I have misinterpreted this idea.
Still, this does not address the question as to where this energy comes from. I liked the example given above regarding two metal balls attached by a wire--if spun and left in space, they will continue to spin for eternity because of all the velocity dot stuff. However, it seems to me that the question we are addressing is where did the energy for that original spin come from? This initial spin force is analogous to the Sun changing the direction of a comet. Where does it get the energy to do that? Do we know enough about energy to answer it? Or does it not need energy?


ps sorry for the long post!
 
  • #50
Nick666 said:
Could this energy of gravity involve somehow dark matter/energy ?
perhaps the "vacuum" energy that is thought to be causing the universe to expand quicker and quicker has something to do with it? seems improbable.
 

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