Where does the galactic distance equation come from?

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The discussion centers on understanding the origin of the galactic distance equation used in a project. The equation, which calculates the distance of data points from defined central galactic coordinates, is derived from the Pythagorean theorem, representing the relationship between the coordinates in a circular format. The user seeks clarification on how the distance (d) fits into the rearranged equation of a circle. It is confirmed that the distance is indeed the hypotenuse in the context of the equation. The conversation emphasizes the connection between the equation and basic geometric principles.
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I'm currently working on my final year project, and one of the little bits to do is to see if certain data points fall within a circle with my own defined radius and central co-ordinates. I've been given the equation to use:

d = \frac{\sqrt{(l-l_{0})^2 + (b-b_{0})^2}}{r}

where l_{0} and b_{0} are my central galactic co-ordinates, r is my radius (in degrees) and d is the distance the data point is from the central co-ordinates (also in degrees) - if d is less than 1, then the point is within my radius.

Although I don't need to, I'd just like to know where the equation comes from! I can see how the right hand side of the equals is a rearrangement of the equation of a circle, but I don't see how the distance is put in. Any help is appreciated!
 
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I realized that it must be Pythagoras, as that's where the equation for a circle comes from, it was more the fact that - when rearranged from the equation - the hypotenuese would be r^2d^2. Since it is normally just r^2, I wasn't sure if you were able to just put the distance (d^2) in.
 
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