Where Does the N in Faraday's Law of Induction Go?

[dbag123]

Hello

Lets take an example: imagine a horizontal magnetic field, then a wire of length L. I push the wire with a force F through the field perpendicularly with respect to the magn. field for a distance of dS.

EMF = work/charge

--> F*dS/I*dt, where F = flux density*current*lenght of conductor

--> Currents cancel each other out and Lenght of conductor multiplied by the distance moved = area

-->we are left with emf in simplified form of B*A/dt, and B*a = the change in magnetic flux
--> also add the minus from lenz's law

My question is Where does the N, or number of turns go?
Thanks

 

[Mister T]

In your example $N$ is the number of wires, you chose $N=1$.

 

[dbag123]

Thank you