Where is the gravitational potential energy?

AI Thread Summary
The discussion centers on the confusion regarding the location of gravitational potential energy (PE) in relation to kinetic energy (KE) of a projectile after it exits a gun. It emphasizes the importance of considering gravitational PE when calculating KE at different points in the projectile's trajectory. Participants note that the small change in height while the projectile travels through the gun is often ignored. Clarifications are provided to ensure understanding of how gravitational PE factors into the overall energy calculations. The conversation highlights the need to account for gravitational effects in projectile motion analysis.
bajerrrr
Messages
4
Reaction score
0
Capture.PNG
I
am confused on where the gravitational potential energy is in this solution. Thank you
 

Attachments

  • Capture.PNG
    Capture.PNG
    14.9 KB · Views: 2,260
Physics news on Phys.org
bajerrrr said:
I
am confused on where the gravitational potential energy is in this solution. Thank you
Note that they are talking about the KE of the projectile immediately after it leaves the gun. You still need to consider gravitational PE if you want to find the KE at other points. (They are ignoring the small change in height of the projectile as it travels through the gun.)
 
ok. thank you very much. I was accounting for the small change in height
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top