Where is the gravitational potential energy?

AI Thread Summary
The discussion centers on the confusion regarding the location of gravitational potential energy (PE) in relation to kinetic energy (KE) of a projectile after it exits a gun. It emphasizes the importance of considering gravitational PE when calculating KE at different points in the projectile's trajectory. Participants note that the small change in height while the projectile travels through the gun is often ignored. Clarifications are provided to ensure understanding of how gravitational PE factors into the overall energy calculations. The conversation highlights the need to account for gravitational effects in projectile motion analysis.
bajerrrr
Messages
4
Reaction score
0
Capture.PNG
I
am confused on where the gravitational potential energy is in this solution. Thank you
 

Attachments

  • Capture.PNG
    Capture.PNG
    14.9 KB · Views: 2,265
Physics news on Phys.org
bajerrrr said:
I
am confused on where the gravitational potential energy is in this solution. Thank you
Note that they are talking about the KE of the projectile immediately after it leaves the gun. You still need to consider gravitational PE if you want to find the KE at other points. (They are ignoring the small change in height of the projectile as it travels through the gun.)
 
ok. thank you very much. I was accounting for the small change in height
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top