Where is the point where the Earth's gravity is cancelled by the moon?

AI Thread Summary
The discussion centers on finding the point between the Earth and the moon where their gravitational forces cancel each other out. The mass of the moon is noted to be 1/81 that of the Earth, prompting calculations based on the gravitational force equation F=GMm/r^2. Participants suggest that the distance to this equilibrium point can be expressed as a ratio of the total distance to the moon. One user emphasizes the need to differentiate the distances in the equation to solve for the exact location. The conversation ultimately aims to clarify the mathematical approach to determining this gravitational balance point.
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Homework Statement


Somewhere between the Earth and the moon is a point where the gravitational attraction of the Earth is canceled by the gravitational pull of the moon. The mass of the moon is 1/81 that of the earth. How far away from the center of the Earth is this point?

a) 8/9 the way to the moon
b) 9/10 the way to the moon
c) 3/4 the way to the moon
d) 80/81 the way to the moon

Homework Equations


F=GMm/r^2


The Attempt at a Solution


GM/r^2=G(1/81)M/r^2-d
 
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I don't really get what that 'd' is doing hangen out there all by itself. If you look at your attempt, you need to have the 'r' on the other side denoted as something different, say for example r', where r' is the distance to the moon. What you're looking (in my opinion) is a ratio of the distances from the Earth to that certain point where the forces or equal and the distance from the moon. Start by multiplying both sides by r'^2 where r' is the distance to the moon.
 
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