Where is this piecewise function discontinuous?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
Ianfinity
Messages
5
Reaction score
0
g(x) = 3 if x < -4
g(x) = 7+x if |x| <or= 4
g(x) = x^4 if x > 4



I know there is a jump discontinuity at x=4. How would I state that in interval notation? Is that even possible or is it good enough to say g(x) is discontinuous at x=4? Basically what I've found is that if x=4 then g(x)=11 and that the limit of x is 256 as x approaches 4 from the right.

This is part of my review for the test I will be having today. Thanks in advance for the help.
 
Physics news on Phys.org
Ianfinity said:
g(x) = 3 if x < -4
g(x) = 7+x if |x| <or= 4
g(x) = x^4 if x > 4


I know there is a jump discontinuity at x=4. How would I state that in interval notation? Is that even possible or is it good enough to say g(x) is discontinuous at x=4? Basically what I've found is that if x=4 then g(x)=11 and that the limit of x is 256 as x approaches 4 from the right.

This is part of my review for the test I will be having today. Thanks in advance for the help.
Hello Ianfinity. Welcome to PF !

Yes, g(x) is discontinuous at x=4.

The limit of g(x) is 256 as x → 4-,

not: the limit of x is 256 as x → 4-.