Where is x^3 + 12x + 5 increasing and decreasing

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Homework Help Overview

The discussion revolves around determining the intervals of increase and decrease for the function f(x) = -x^3 + 12x + 5 within the range -3 < x < 3. Participants are exploring concepts related to derivatives and extreme values of the function.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the potential use of derivatives to identify intervals of increase and decrease. There are inquiries about necessary and sufficient conditions for extrema, as well as the implications of a zero derivative at critical points.

Discussion Status

The conversation is actively exploring the relationship between derivatives and extreme values. Some participants have provided insights into the conditions for identifying extrema, while others are seeking further clarification on these concepts.

Contextual Notes

There is an emphasis on understanding the implications of a zero derivative and the distinction between necessary and sufficient conditions for extrema. The discussion is framed within the constraints of the specified interval for x.

teng125
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Find intervals on which f(x)=-x^3 + 12x +5 , -3<x<3 is increasing and decreasing. Where does the function assume extreme values and what are these values ?

does anybody knows how to do this??
 
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I have the feeling derivatives may be a good idea :smile:

Do you know a necessary and/or sufficient condition for extrema, using derivatives?
 
no,pls explain to me
 
When a function becomes extreme in a point, the tangent line will be horizontal there which means that the derivative of the function is 0 there. Note that this is a one-way argument, an extremum implies a zero derivative but not the other way arround, so this is a necessary condition - though not sufficient.

To check whether it is actually a min or max, you can use the second derivative or investigate whether the function switches from increasing to decreasing or vice versa arround that point.
 

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