Where Should the Third Mass Be Placed to Experience No Net Gravitational Force?

AI Thread Summary
To determine where a third mass (16.0 kg) experiences no net gravitational force between two other masses (43.0 kg at the origin and 11.8 kg at x = 52.8 m), the gravitational forces exerted by M1 and M2 must balance. The gravitational force formula F = G(m1 * m2) / r^2 is applied, where G is the gravitational constant. The user attempts to calculate the forces acting on the third mass and considers its position on the x-axis between 0 and 52.8 m. They seek guidance on whether their approach to solving for the position x is correct. The discussion focuses on the calculations necessary to find the equilibrium point for the third mass.
sheri1987
Messages
47
Reaction score
0

Homework Statement



M1 is a spherical mass (43.0 kg) at the origin. M2 is also a spherical mass (11.8 kg) and is located on the x-axis at x = 52.8 m. At what value of x would a third mass with a 16.0 kg mass experience no net gravitational force due to M1 and M2?


Homework Equations



F= G(m1 * m2)
r^2


The Attempt at a Solution



G = 6.67*10-11, m1 = 43, m2= 11.8 and r^2 = 52.8 ...I plugged all of this into solve for F, then I think I have to use this equation again and multiply the top by a m3 and solve for x using the F I found previous...is this right, if not could you help me out? Thanks
 
Physics news on Phys.org
suppose m3 is located at some value x that is between 0 and 52.8m.

What is the force m1 exerts on m3? What is the force m2 exerts on m3? Take right to be positive... left to be negative.
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

How much force does the 20 kg block exert on the 10 kg block?
Replies
17
Views
2K
Magnitude of net Gravitational Force
Replies
1
Views
5K
Why used $\cos\theta$ for $\text{y}$ axis or, gravitational force?
Replies
2
Views
2K
Newton's Second Law (Pulley Sustem)
Replies
3
Views
2K
Calculating Net Force of 3 Blocks in an Elevator
Replies
9
Views
2K
Determine the mass of the planet using Newton’s Law of Universal Gravitation
Replies
2
Views
3K
How to find the equilibrium position of three masses (two of them fixed)?
Replies
4
Views
2K
Calculating Masses Using Gravitational Force Equations
Replies
5
Views
1K
Finding the net gravitational force on a rocket....
Replies
5
Views
2K
Finding the net gravitational force with Vector Notation
Replies
2
Views
2K

Hot Threads

Recent Insights

Back
Top