Where Should You Stand to Avoid Wave Action in a Water Tank Experiment?

[hallowon]

Homework Statement

In a large water tank experiment, water waves are generated
with straight, parallel wave fronts, 3.00 m apart. The
wave fronts pass through two openings 5.00 m apart in a
long board. The end of the tank is 3.00 m beyond the board.
Where would you stand, relative to the perpendicular
bisector of the line between the openings, if you want to
receive little or no wave action?

Homework Equations

xn represent the horizontal distance between the perpendicular bisector drawn to the line joining the two sources and the nth nodal line
λ=(Xn/L)(d/n-0.5)

Answer is 1.25m

The Attempt at a Solution

λ=3.0m
L=3.0m
d=5.0m

I got stuck since i don't know which nodal line(n)

 

[AvroArrow]

that I should use. I thought of using n=1 but then the equation would give me a negative number. Can someone please guide me on this question?

 

[kerimek]

is the one I'm looking for

I would recommend standing at a distance of 1.25 meters from the perpendicular bisector of the line between the two openings. This is because at this distance, the nth nodal line will be located at the opening, resulting in little or no wave action. This can be calculated using the equation λ=(Xn/L)(d/n-0.5), where Xn is the horizontal distance between the perpendicular bisector and the nth nodal line, L is the distance between the two openings, and d is the distance between the openings and the end of the tank. By setting n=1 and plugging in the given values, we can solve for Xn and get the desired distance of 1.25 meters from the perpendicular bisector. This will ensure minimal wave action and provide accurate and reliable results for the experiment.