Which Complex Has the Greatest Oxidizing Power: CrO42-, MnO42-, or FeO42-?

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Discussion Overview

The discussion centers on the comparative oxidizing power of the complexes CrO42-, MnO42-, and FeO42-. Participants explore the factors influencing oxidizing power, including redox potentials and electronegativity, while seeking to establish a ranking of these complexes without specific data.

Discussion Character

  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • One participant notes that the oxidizing power is related to the redox potential of the redox couples, suggesting that higher redox potential indicates a stronger oxidizer.
  • Another participant mentions that MnO42- is commonly used for oxidations in organic chemistry, while CrO42- is used in its anhydride form, and expresses uncertainty about the use of FeO42-.
  • A participant seeks to rank the complexes based solely on their oxidation states, indicating a need for further guidance on how to proceed without data.
  • One participant proposes that electronegativity can be used to rank the oxidizing power, suggesting that Fe is more electronegative than Mn, which is more electronegative than Cr, leading to a proposed order of FeO42- > MnO42- > CrO42-.

Areas of Agreement / Disagreement

Participants express differing views on how to determine the oxidizing power, with some relying on redox potentials and others on electronegativity. No consensus is reached on the definitive ranking of the complexes.

Contextual Notes

The discussion highlights the dependence of oxidizing power on factors such as redox potential and electronegativity, but lacks specific data to support the claims made. The influence of solution pH on the redox couples is also mentioned but not elaborated upon.

hgnk708113
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You have to show your attempts at answering the question, this is a forum policy. Also, all homework like questions should go to homework forum.
the three complexes CrO42- Mno42- FeO42-
which is the order for their oxidizing power? And why?
 
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The oxidizing power depends on the redox potential of the redox couples considered, the higher the redox potential, the more the metal will give oxygen atoms. So if you know the redox potential of the couples including those 3 complexes , you know which one is the more oxidizing. Of course one complex can be included in two or more couples, it usually depends on the solution's pH.
I'm not sure of the order of the oxidizing power here, but MnO42- is the most currently used for oxidations. In organic chemistry, we also use chromium, but under its anhydride form CrO3 with an organic solvant, not under its complex form. And I never heard about using FeO42- for oxidations.
Hope I helped you.
 
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Thanks for your reply.
But I still need to rank their order without data and need to explain my answer.
I already know their oxidation state are +6. And then I don't know how to proceed.
 
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Okay, so without data you may use the fact that the more an element is electronegative, the higher will be is oxidizing power. And knowing the atomic number of the three elements considered (24Cr, 25Mn, 26Fe), you can say that the more electronegative is Fe, followed by Mn and then Cr, so the order for the oxidizing power of those elements : Fe>Mn>Cr.
If we suppose that because they are under "the same complex form" (XO42- where X is the element), the oxidizing power order remains the same, I would class them like that :
FeO42- > MnO42- > CrO42-
 
Oh I see thank you.
 

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