Which Element in Period 2 Has the Highest Density in Its Standard State?

AI Thread Summary
In Period 2, the element with the highest density in its standard state is Boron, with a density of 2.34 g/cm^3. Gases such as Nitrogen, Oxygen, Fluorine, and Neon were excluded from consideration due to their gaseous state at standard conditions. The densities of solids in this period were provided, with Beryllium and Carbon also noted for their densities of 1.85 g/cm^3 and 2.267 g/cm^3, respectively. Although diamond, a form of carbon, has a higher density of about 3.5 g/mL, it is not considered in standard state calculations due to its thermodynamic instability. Therefore, Boron is confirmed as the densest element in Period 2 under standard conditions.
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Homework Statement


Which of the elements, from the second period, has the highest density in its standard state?


Homework Equations


Standard state is gas at 1 atm, concentration of 1 M for liquid, or pure substance at 25C and 1 atm.


The Attempt at a Solution


I thought that N, O, F, and Ne could be removed from possibilities because they are gases. Then I looked it up and found Boron had the largest density, but that was incorrect.
 
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What did you find for densities for all the solids in that period?
 
I found:
Li: .534 g/cm^3
Be: 1.85 g/cm^3
B: 2.34 g/cm^3
C: 2.267 g/cm^3
N: .00125 g/cm^3
O: .00149 g/cm^3
F: .001696 g/cm^3
Ne: .0008999 g/cm^3
 
I would say boron in the standard state is the densest.

There is a little catch here - diamond (which is a pure carbon) has much higher denisty, something like 3.5 g/mL. But diamonds are not thermodynamically stable - they convert to graphite. Conversion is so slow, that for all practical purposes diamonds are stable - but thermodynamically they are not. Thus they are not standard state of the carbon.
 
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