Which forces does work as a car brakes?

AI Thread Summary
The discussion centers on the forces that perform work when a car brakes. It clarifies that while the normal force does not do work due to being perpendicular to motion, the frictional force does work because it opposes the car's motion. When a car brakes, kinetic friction is at play, as the wheels skid rather than roll, indicating that kinetic friction is responsible for slowing the vehicle. The confusion arises from the distinction between static and kinetic friction, with the emphasis on kinetic friction doing work during braking. Overall, the key takeaway is that kinetic friction is the force that performs work to stop a moving car.
okgo
Messages
61
Reaction score
0

Homework Statement


Which forces does work?
http://www.screencast.com/users/ntrinh3/folders/Jing/media/3f09a85d-142c-4f73-a8a8-1ad506d5c2b8


Homework Equations


W=fdcos(theta)


The Attempt at a Solution


I always thought normal and friction does no work because it is perpendicular to motion. What gives?
 
Physics news on Phys.org
yes the normal force does no work

But the frictional force is opposing motion (anti-parallel to the motion), so it must do work to slow the mass down.
 
When a car brakes, isn't it in motion and using kinetic friction to stop, and not static friction?
Static friction causes rolling motion in wheels, but there is no rolling motion so it skids. So shouldn't kinetic friction do work and not static? I'm a bit confused on the two concept.
 
okgo said:
When a car brakes, isn't it in motion and using kinetic friction to stop, and not static friction?
Static friction causes rolling motion in wheels, but there is no rolling motion so it skids. So shouldn't kinetic friction do work and not static? I'm a bit confused on the two concept.

Had the car been stationary, static friction would be acting, but the car in motion, so kinetic friction is doing work. There is relative motion between the wheels and the ground.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top