Which is Smaller: Comparing Mathematical Expressions A and B?

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Discussion Overview

The discussion revolves around comparing two mathematical expressions, A and B, defined by alternating series and sums of reciprocals. Participants are exploring the values of these expressions and attempting to determine which is smaller. The scope includes mathematical reasoning and analysis of series.

Discussion Character

  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Some participants express that A can be rewritten in terms of harmonic numbers, suggesting that A equals the difference between two harmonic sums: \( H_{2014} - H_{1007} \).
  • Others propose that A can also be expressed as \( H_{2013} - H_{1007} \), leading to a similar conclusion about the relationship between A and B.
  • There are repeated assertions that A is less than B based on these formulations, although the reasoning and steps are not universally agreed upon.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the comparison between A and B, as different formulations and interpretations of A lead to conflicting conclusions about which expression is smaller.

Contextual Notes

The discussion includes potential ambiguities in the definitions of harmonic numbers and the limits of the series involved, which may affect the comparison. Some steps in the reasoning are not fully resolved.

Albert1
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$A=1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}+----+\dfrac{1}{2013}-\dfrac{1}{2014}$

$B=\dfrac{1}{1007}+\dfrac{1}{1008}+----+\dfrac{1}{2013}+\dfrac{1}{2014}$Compare A and B,which on is smaller ?
 
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Albert said:
$A=1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}+----+\dfrac{1}{2013}-\dfrac{1}{2014}$

$B=\dfrac{1}{1007}+\dfrac{1}{1008}+----+\dfrac{1}{2013}+\dfrac{1}{2014}$Compare A and B,which on is smaller ?

[sp]Is...

$\displaystyle A = 1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + ... + \frac{1}{2013} - \frac{1}{2014} = H_{2014} - H_{1007} =$

$ \displaystyle = \frac{1}{1008} + \frac{1}{1009} + ... + \frac{1}{2014}\ (1)$

... so that is A < B...[/sp]

Kind regards

$\chi$ $\sigma$
 
Last edited:
chisigma said:
[sp]Is...

$\displaystyle A = 1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + ... + \frac{1}{2013} - \frac{1}{2014} = H_{2013} - H_{1007} =$

$ \displaystyle = \frac{1}{1008} + \frac{1}{1009} + ... + \frac{1}{2013}\ (1)$

... so that is A < B...[/sp]

Kind regards

$\chi$ $\sigma$
$\displaystyle A = H_{2014} - H_{1007}$
 
Albert said:
$A=1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}+----+\dfrac{1}{2013}-\dfrac{1}{2014}$

$B=\dfrac{1}{1007}+\dfrac{1}{1008}+----+\dfrac{1}{2013}+\dfrac{1}{2014}$Compare A and B,which on is smaller ?
let $C=1+\dfrac{1}{2}+\dfrac{1}{3}+----+\dfrac{1}{1007}$
then :
$A+C=1+\dfrac{1}{2}+\dfrac{1}{3}+---+\dfrac{1}{1007}+\dfrac{1}{1008}+---+\dfrac{1}{2013}+\dfrac{1}{2014}$
$B+C=1+\dfrac{1}{2}+\dfrac{1}{3}+---+\dfrac{1}{1007}+\dfrac{1}{1007}+\dfrac{1}{1008}+---+\dfrac{1}{2013}+\dfrac{1}{2014}$
$B+C-(A+C)=B-A=\dfrac{1}{1007}$
$\therefore B>A$
 

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