# Who am I?

1. Mar 10, 2005

### hedons

x/1 = x+1/x

Last edited: Mar 11, 2005
2. Mar 11, 2005

### RandallB

0/0 . . or
SqrRoot of -0

3. Mar 11, 2005

### K.J.Healey

4. Mar 11, 2005

### nnnnnnnn

x/1 = x

x = x - 1/x
->0=-1/x...
unless you take the limit you are nobody...

5. Mar 12, 2005

### hemmul

x=Âħsqrt(1/(1-1))

you're the 4 grade student, who just studied what an "equation" is

6. Mar 12, 2005

### theCandyman

Is that written as $$\frac {x}{1} = x + \frac{1}{x}$$ or is it supposed to be $$\frac {x}{1} = \frac{x+1}{x}$$?

7. Mar 14, 2005

### K.J.Healey

oh yea, cause if its the second one then its the golden ratio. 1.61828 or whatever.

8. Mar 15, 2005

### ArielGenesis

then if it's the second

x^2 = x+1
x^2-x-1 =0
x=(1(+-) (((-1)^2)-(4)(1)(-1))^0.5) (2(1))^-1
x= (1(+-)(5^0.5))/2
interesting ???

9. Mar 26, 2005

### SolidFist

An anomoly, that's what you are!

10. Mar 29, 2005

### vikasj007

i think it should be infinity. putting value of xas infinite we will satisfy the equation.

11. Mar 29, 2005

### xJuggleboy

Are we ever getting a answer here???

12. Apr 11, 2005

### pack_rat2

x = 1/x has no solution. For x = 1 + 1/x, x = ~1.618 (the "golden ratio").

13. Apr 11, 2005

### bjr_jyd15

?! I think x=1 is a solution.

14. Apr 11, 2005

### theCandyman

So is $$x = -1$$.

15. Apr 11, 2005

### hypermorphism

I believe he meant to say 0=1/x.

16. Apr 12, 2005

### pack_rat2

Ahhhh....x = 1 is so obvious. but x = -1 doesn't work.