Why a timelike vector and a null vector cannot be orthogonal?

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A timelike vector and a null vector cannot be orthogonal because a null vector, defined by n² = 0, does not yield a zero scalar product with a timelike vector. The scalar product lμnμ must be shown to be non-zero, which contradicts the assumption of orthogonality. The discussion emphasizes the importance of considering the components of the vectors and the metric used in calculations. The relationship between the vectors can be analyzed using the properties of the cosine function in the context of their scalar product. Understanding these properties clarifies why the two types of vectors cannot be orthogonal.
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Why a timelike vector and a null vector cannot be orthogonal?
Isn't a null vector orthogonal to any vector, by definition? Anyway, each component of a vector is multiplied by zero, so in the end the sum is zero.
 
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Null 4-vector:
n^{\mu};n^{2}=:n^{\mu}n_{\mu}=0 (1)

Timelike 4-vector:
l^{\mu};l^{2}=:l^{\mu}l_{\mu}<0 (2)

Prove that
l^{\mu}n_{\mu} \neq 0(3)

HINT:Use components and the property of the 'cosine' function.


Daniel.

P.S.Esti varza...
 
HINT:'cosine' appears in the expression of the scalar product between those vectors (space components).Pay attention with the metric...

Daniel.
 
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