Why are orbits of Comets unstable?

AI Thread Summary
Comets have unstable orbits primarily due to their highly elliptical paths and the influence of multiple gravitational forces from nearby celestial bodies. Unlike planets, which have stable orbits, comets can experience significant changes in trajectory due to these gravitational interactions, making them more susceptible to collisions. The characteristics of comets, such as their eccentricity and varying orbital energy, contribute to this instability. Additionally, factors beyond gravity, such as outgassing and solar radiation pressure, can further alter a comet's path. Understanding these dynamics is crucial for assessing potential hazards posed by comets during their travels.
Riccardo K

Homework Statement


The orbits of the planets remains extremely stable over long times however this not always true for comets. Can you explain why not? What hazards might they encounter during their travels?

Homework Equations


None

The Attempt at a Solution


I think that due to the comet's not having a determined orbit while the comet is traveling it gets affected by multiple gravitational forces so its path is changed and it might crash into another object.
 
Physics news on Phys.org
You'll have to expand a bit on what you mean by "comet's not having a determined orbit while the comet is traveling". The gravitational influence comment is correct, but could also use some additional fleshing out. For example, what is it about a comet that makes it susceptible to these gravitational influences whereas planets are relatively unaffected despite also constantly being subjected to multiple changing gravitational influences.

You might want to consider the various characteristics of a typical comet as compared to those of say, planets and asteroids (orbit energy, eccentricity, orientation). Are there things other than gravity that influence them? Do they change over different parts of the orbit?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top