- #1
kdlsw
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I do understand the probability of a wave function ψ is given by ∫ψ* ψ d3x, which after normalization is equal to 1. However, I then saw the following, ∫ψn* ψm=δmn
Here is my understanding, the discussion is about discrete eigenfunction and value as expressed in m and n, ψn and ψm are two discrete wave functions, and with the orthonormal method, they are arranged to be ∫ψn* ψm=1 when m=n and 0 when m≠n.
What I don't understand is, doesn't such form equal to ∫ψ* ψ d3x ? Where the complex conjugate and normal wave function part comes from the same ψ. What is the point of discussing the complex conjugate of a different wave function ψn* in the first place? Are ψn ψm just two different states of the same wave function ψ?
Thanks a lot
Here is my understanding, the discussion is about discrete eigenfunction and value as expressed in m and n, ψn and ψm are two discrete wave functions, and with the orthonormal method, they are arranged to be ∫ψn* ψm=1 when m=n and 0 when m≠n.
What I don't understand is, doesn't such form equal to ∫ψ* ψ d3x ? Where the complex conjugate and normal wave function part comes from the same ψ. What is the point of discussing the complex conjugate of a different wave function ψn* in the first place? Are ψn ψm just two different states of the same wave function ψ?
Thanks a lot