Why are the coordinate axis different for block M1 and M2 in this scenario?

  • Thread starter Thread starter Miike012
  • Start date Start date
  • Tags Tags
    Axis Coordinate
AI Thread Summary
The discussion centers on the differing coordinate axes for blocks M1 and M2, with confusion arising over the designation of directions. It is clarified that separate coordinate systems can be used for disconnected bodies, but when they are connected, a unified axis is preferable due to their coupled motions. The horizontal displacement of block M1 corresponds to the vertical displacement of block M2, necessitating the same variable name for both. This approach simplifies the analysis of their movements, as any change in one block's position directly affects the other. Understanding the relationship between the blocks is crucial for accurate calculations in this scenario.
Miike012
Messages
1,009
Reaction score
0
I am confused how they picked the direction right of block M1 to be -x and the downward direction of block M2 to be +x..?

I didn't know that one could create two different coordinate axis.

Correct me if I am wrong but it seems that if you are working with two diff body's that are not in contact you can create diff axis for both body's.. but if two body's are in contact then you have to use the same axis for both body's?
 
Physics news on Phys.org
What's block M1? What's block M2? What are they up to? Who are "they"? Without context, your statements are vague and your questions unanswerable.
 
sorry forgot to add the picture... here it is..
 

Attachments

  • phy.JPG
    phy.JPG
    9.5 KB · Views: 383
Okay. In this situation there are two separate objects being considered. They are connected by a string (or rope, or cable, or however it's defined). Because they are so connected, their motions are coupled. That is, any change of displacement of one is going to be identical to the displacement of the other, in magnitude if not direction. This being so, it would make sense to choose the same variable name for both displacements (they will have equal values at all times). x is the value of the horizontal displacement of block M1, and it's also the vertical displacement of block M2. Does that work for you?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top