Why are the last two digits of the mass of an electron in parentheses?

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Discussion Overview

The discussion centers around the notation used for the mass of an electron, specifically the significance of the last two digits being presented in parentheses in the value 0.510 998 9461(31) MeV/c². Participants explore the implications of this notation and its relation to uncertainty in measurements.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant questions the meaning of the parentheses in the mass of the electron, suggesting it might indicate uncertainty similar to the format (0.510 998 9461 ± 0.000 000 0031) MeV/c².
  • Another participant clarifies that the notation does not imply a ± value but indicates that the last two digits are uncertain.
  • A reference to concise notation is provided, explaining that parentheses indicate the numerical value of the standard uncertainty related to the last digits of the quoted result.
  • One participant acknowledges a potential misunderstanding based on the clarification provided by another participant.
  • A repeated reference to concise notation reinforces the explanation of how uncertainty is expressed in scientific measurements.

Areas of Agreement / Disagreement

Participants exhibit some disagreement regarding the interpretation of the parentheses, with one participant initially misunderstanding its meaning. However, there is a shared understanding of the notation's purpose after clarification.

Contextual Notes

Participants reference external sources to explain the notation, indicating that the discussion is informed by established conventions in scientific communication.

Who May Find This Useful

This discussion may be useful for individuals interested in scientific notation, measurement uncertainty, and the conventions used in reporting physical constants.

Mason Smith
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According to Wikipedia, the mass of an electron is 0.510 998 9461(31) MeV/c2. Why are the last two digits of this number in parenthesis? Is this the same thing as saying (0.510 998 9461 ± 0.000 000 0031) MeV/c2.
 
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Mason Smith said:
± 0.000 000 0031

No, it does not mean that. It means that it is approximately equal to 0.510 998 946131 but the last two decimal places are uncertain.
 
Use of concise notation (from https://physics.nist.gov/cgi-bin/cuu/Info/Constants/definitions.html)

If, for example, y = 1 234.567 89 U and u(y) = 0.000 11 U, where U is the unit of y, then Y = (1 234.567 89 ± 0.000 11) U. A more concise form of this expression, and one that is in common use, is Y = 1 234.567 89(11) U, where it understood that the number in parentheses is the numerical value of the standard uncertainty referred to the corresponding last digits of the quoted result.
 
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Lord Jestocost said:
Use of concise notation (from https://physics.nist.gov/cgi-bin/cuu/Info/Constants/definitions.html)

If, for example, y = 1 234.567 89 U and u(y) = 0.000 11 U, where U is the unit of y, then Y = (1 234.567 89 ± 0.000 11) U. A more concise form of this expression, and one that is in common use, is Y = 1 234.567 89(11) U, where it understood that the number in parentheses is the numerical value of the standard uncertainty referred to the corresponding last digits of the quoted result.
This helped a lot. Thank you for the reference.
 

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