Why can maximum shear stress in a web be replaced by the average shear stress?

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Discussion Overview

The discussion revolves around the use of average shear stress versus maximum shear stress in the design of steel beams, particularly in the context of calculating allowable shear stress in web sections. Participants explore the calculations and reasoning behind these approaches, examining specific examples and numerical results.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant questions the rationale for using average web shear stress (V/dt) instead of maximum shear stress (VQ/It) and expresses confusion over their calculations showing the average greater than the maximum.
  • Another participant suggests that maximum shear stress at the neutral axis is approximately equal to average shear stress when considering the web area only.
  • A participant provides specific calculations for a wide flange beam, detailing the average and maximum shear stress values obtained and questioning the closeness of these results.
  • Further calculations are shared, including the determination of shear force (V), moment of inertia (I), and the first moments (Q) for the beam, leading to a comparison of maximum and average shear stress values.
  • One participant concludes that the calculated maximum and average shear stress values are close enough to support the approximation of using average shear stress, pending confirmation of their calculations.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the appropriateness of using average shear stress over maximum shear stress, as there are differing interpretations of the calculations and their implications. Some participants support the approximation while others express uncertainty.

Contextual Notes

There are potential limitations in the calculations provided, including assumptions about the beam geometry and loading conditions, as well as the specific definitions of shear stress being used. The discussion does not resolve these aspects.

mtnmama
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I've been reading my strength of materials text about design of steel beams. I understand everything up to the point where the text tells me to use the average web shear stress (V/dt) instead of max shear stress (VQ/It) to determine if a given beam is within the allowable shear stress. I calculated both to determine how close they are and found the average greater than the max! I've checked several times and don't see an error. What am I missing?
 
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mtnmama said:
I've been reading my strength of materials text about design of steel beams. I understand everything up to the point where the text tells me to use the average web shear stress (V/dt) instead of max shear stress (VQ/It) to determine if a given beam is within the allowable shear stress. I calculated both to determine how close they are and found the average greater than the max! I've checked several times and don't see an error. What am I missing?
Are you using a wide flange (I) beam? Max shear stress at the neutral axis (VQ/It) is approximately equal to the average shear stress when using the web area only (V/Aw).
 
Last edited:
Yes, it is a wide flange. When I calculate an average and a max stress on the flange of a 8 ft section of W18 x 50 with a uniform load of 1.85 klb/in I get an average of 16.22 klb/sq in. The max I get is 6.56 klb/sq in. Is that considered close, or have I made an error somewhere?
 
Please show your working.
 
I found some errors in Q. What I get now is:

V = wL/2 = [1.85 klb/in * 8 ft *12 in/ft]/2 = 88.80 kips
I = 400 in^4 (table)
Q = sum of first moments of upper half of beam, ie the flange and half the web
= Q of flange + Q of 1/2 web
= A of flange x y to centroid + A of 1/2 web x y to centroid
= (7.495 in * .57) * 8.71 + (8.425*.355*4.2125)
= 37.21 + 12.60
= 49.81 in^3

Max stress = VQ/(It) = 88.80 * 49.81 / (800 * .355) = 15.57 ksi

Avg stress = V/A of web = 88.89/(.355 * 15.42) = 16.22 ksi

These two values are close enough to verify that the max stress can be approximated by avg stress. If you don't see any errors in my equations, I will continue to use the approximation with confidence.

Thank you.
 

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