Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Why correct this inequality log(d/d-1)>(1/d)?

  1. Feb 19, 2014 #1
    Why correct this inequality,

    log(d/(d-1))>1/d for d≥2?
     
    Last edited: Feb 19, 2014
  2. jcsd
  3. Feb 19, 2014 #2

    maajdl

    User Avatar
    Gold Member

    There must be a mistake in your question since d/d=1
    You corrected the mistake.
     
    Last edited: Feb 19, 2014
  4. Feb 19, 2014 #3
    multiplication comes before addition.
    I see d/d-1 as [tex]\frac{d}{d} -1[/tex]log 0 = who-knows-what
     
  5. Feb 19, 2014 #4

    maajdl

    User Avatar
    Gold Member

    Well, check first that this inequality is correct for d=2.
    Then prove that the function log(d/(d-1)) will continue to be > than 1/d for d>2.
    You could do that by analysis the derivative.

    Get insight by making a plot of these functions.

    Alternatively, study the function log(d/(d-1))-1/d .
    Calculate its value for d=2, and analyze its behavior for d>2 .
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Why correct this inequality log(d/d-1)>(1/d)?
  1. Solve for d (Replies: 17)

Loading...