Why Did My Calculation of Temperature Change Result in the Wrong Answer?

[punk_rawk_jazz]

Does anyone know why I end up with the wrong answer?
The question is:

Determine the temperature change: 10 kg of water loses 232 kJ or heatQUOTE]

I went delta q is equal to m c delta t, the derived the equation delta t is equal to delta q divded by mc. I therefore did the math as 232 kJ divided by (10 kg times 4.2 x 10 ^3 j/kg C) and got 9.7 x 10 ^4, when the answer was supposed to be 5.5. Does anyone know what I did wrong??


Thank you in advance

 

[Sirus]

Make sure you are consistent in units. Also remember to include signs in your calculations to indicate gain/loss of energy.

 

[nofx]

Hope this helps

Firstly just change the 232 kJ into joules so you that have 232000 J.

q = mc delta t
232000 = 10 * 4200 * delta t
delta t = 232000/10*4200
delta t = 232000/42000
delta t = 5.5

 

[Diane_]

Was there any particular reason why you posted this twice?

 

[punk_rawk_jazz]

Nope I just mest up...