Why did they use these formulas for energy of electron.

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Discussion Overview

The discussion centers around the appropriate formulas to use for calculating the energy of electrons in the context of an electron microscope, specifically when determining the energy required to achieve a wavelength of 10.0 pm. The scope includes homework-related problem-solving and the application of relevant physics equations.

Discussion Character

  • Homework-related
  • Technical explanation

Main Points Raised

  • One participant suggests using the equation E = hv = hc/lambda to find energy based on wavelength, but questions the necessity of using additional equations for velocity and kinetic energy.
  • Another participant clarifies that the equation E = hv = hc/lambda applies only to photons, implying that different equations are needed for electrons.
  • There is a discussion about the need to use specific equations for electrons, with one participant expressing confusion over treating electrons as photons.
  • A later reply emphasizes that the equations for kinetic energy and momentum must be used for massive particles like electrons, contrasting them with massless particles like photons.

Areas of Agreement / Disagreement

Participants generally agree that different equations are necessary for electrons compared to photons, but there is some confusion regarding the application of these equations in specific contexts. The discussion remains unresolved regarding the best approach to solving the problem.

Contextual Notes

There are limitations in the understanding of when to apply certain equations, particularly in distinguishing between massive particles and massless particles, and the implications of using the wrong equations in problem-solving.

cloudage
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Homework Statement


An electron microscope employs a beam of electrons to obtain an image of an object. What energy must be imparted to each electron of the beam to obtain a wavelength of 10.0pm?



Homework Equations


1. E = hv=hc/lambda
2. lambda = h/(mv)
3. KE = .5mv^2



The Attempt at a Solution


In this problem I thought you could use the first equation to find the energy with the specific wavelength of 10pm. However, the workbook goes through equations 2 and 3 to first find the velocity and then find the kinetic energy. The answers come out very different, so I must be thinking wrong. Can anyone help me understand this?
Since I am solving for energy, why do I need to go through equations 2 and 3?
 
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cloudage said:
1. E = hv=hc/lambda
This only applies to photons.
2. lambda = h/(mv)
3. KE = .5mv^2
For an electron, you'll need these two equations.
 
So whenever they say "electrons" I need to use them? That makes sense, I figured the electrons were being emitted as photons so I thought of them as photons.

Thank you for your help, I see why I got the wrong answer on a couple of other problems now too:smile:
 
cloudage said:
So whenever they say "electrons" I need to use them?
For any kind of massive particle. (A photon has no mass.)
That makes sense, I figured the electrons were being emitted as photons so I thought of them as photons.
Yikes, don't do that. :wink:
 

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