Why did they use these formulas for energy of electron.

AI Thread Summary
The discussion focuses on the energy calculations for electrons in an electron microscope, specifically how to achieve a wavelength of 10.0 pm. The initial confusion arises from the use of the equation E = hv = hc/lambda, which applies to photons, rather than the appropriate equations for massive particles like electrons. To find the energy, it's necessary to first determine the velocity of the electrons using lambda = h/(mv) and then calculate kinetic energy with KE = 0.5mv^2. The distinction between photons and electrons is crucial, as electrons should not be treated as photons in these calculations. Understanding this difference clarifies the correct approach to solving similar problems in the future.
cloudage
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Homework Statement


An electron microscope employs a beam of electrons to obtain an image of an object. What energy must be imparted to each electron of the beam to obtain a wavelength of 10.0pm?



Homework Equations


1. E = hv=hc/lambda
2. lambda = h/(mv)
3. KE = .5mv^2



The Attempt at a Solution


In this problem I thought you could use the first equation to find the energy with the specific wavelength of 10pm. However, the workbook goes through equations 2 and 3 to first find the velocity and then find the kinetic energy. The answers come out very different, so I must be thinking wrong. Can anyone help me understand this?
Since I am solving for energy, why do I need to go through equations 2 and 3?
 
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cloudage said:
1. E = hv=hc/lambda
This only applies to photons.
2. lambda = h/(mv)
3. KE = .5mv^2
For an electron, you'll need these two equations.
 
So whenever they say "electrons" I need to use them? That makes sense, I figured the electrons were being emitted as photons so I thought of them as photons.

Thank you for your help, I see why I got the wrong answer on a couple of other problems now too:smile:
 
cloudage said:
So whenever they say "electrons" I need to use them?
For any kind of massive particle. (A photon has no mass.)
That makes sense, I figured the electrons were being emitted as photons so I thought of them as photons.
Yikes, don't do that. :wink:
 
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