Why Do Cosine and Sine Give Different Angles for the Same Vector?

AI Thread Summary
The discussion centers on the calculation of angles for the vector a = (3, -3) using cosine and sine functions. The magnitude of the vector is determined to be 3√2. While the cosine function yields an angle of 45 degrees, the sine function provides -45 degrees, which translates to 315 degrees when considering the positive angle. The inconsistency arises because arccos produces angles between 0 and 180 degrees, whereas arcsin provides angles between -90 and 90 degrees. The correct approach emphasizes that for vectors in the fourth quadrant, the angle should be expressed as 315 degrees.
k_squared
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Homework Statement



Find the magnitude of a and the smallest positive angle theta from the positive x-axis to the vector OP that corrosponds to a.

a= (3,-3)

Homework Equations



a1 = ||a|| * cos theta
a2 = ||a|| * sin theta
3. The Attempt at a Solution

||a|| = \sqrt{}(9+9) = 3\sqrt{}2
a1 = 3\sqrt{}2 * cos theta

=1/\sqrt{}2 =acos = 45 degrees.

However doing the other side of the equation...

a2= -1/\sqrt{}2 = asin = -45 degrees = 315 degrees, which is the right answer. I thought they were supposed to be consistent...
 
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k_squared said:

Homework Statement



Find the magnitude of a and the smallest positive angle theta from the positive x-axis to the vector OP that corrosponds to a.

a= (3,-3)

Homework Equations



a1 = ||a|| * cos theta
a2 = ||a|| * sin theta
3. The Attempt at a Solution

||a|| = \sqrt{}(9+9) = 3\sqrt{}2
a1 = 3\sqrt{}2 * cos theta

=1/\sqrt{}2 =acos = 45 degrees.

However doing the other side of the equation...

a2= -1/\sqrt{}2 = asin = -45 degrees = 315 degrees, which is the right answer. I thought they were supposed to be consistent...
arccos produces an angle between 0 and 180 degrees, while arcsin produces an angle between -90 and + 90 degrees. Since your vector is in the fourth quadrant, an angle of 45 degrees wouldn't be right, nor would -45 degrees, since the problem asks for a positive angle.
 
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