Why Do We Divide Change in Volume by Original Volume in Bulk Modulus Formula?

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The discussion centers on the concept of bulk modulus, defined as the ratio of pressure change to the relative change in volume. Dividing the change in volume by the original volume ensures that the bulk modulus is a property independent of sample size, allowing for consistent comparisons across different materials. The example of stacking springs illustrates how compressive properties remain constant while the overall movement increases with additional springs. It highlights that the force required to compress objects varies with their size, emphasizing the importance of relative measurements. Understanding these principles is crucial for accurately assessing material behavior under compressive forces.
AakashPandita
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bulk modulus = Δp/ΔV/V

Why do we need to divide change in volume by the original volume?

why is it important?
 
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Say you have a spring with spring constant k that is one inch tall with no weight on it. Now say you put on top the spring a mass which compresses the spring 1/10 an inch. Now stack two such springs on top of each other and place the same mass on top of the stacked springs. It should not be too hard to convince yourself that the two springs together will now compress by 2/10 an inch. The compressive properties of the springs, k, has not changed but with more springs you get more movement. Compressive material acts like the springs, more springs stacked on top of one another you get more movement for a given force.

If we apply compressive forces to some object we want to know how much it will change shape but that depends on the size and its properties.

Does this make sense or help?
 
Because if we used just Δp/ΔV, the bulk modulus would depend on the size of the sample. We want a quantity that is independent of the sample size.
 
say i have 2 iron blocks. 1 is a small block and other is huge.
I need to decrease each of their volumes by 10 m^3.
would the force required in each case be the same or not?
 
say i have 2 iron blocks. 1 is a small block and other is huge.
I need to decrease each of their volumes by 10 m^3.
would the force required in each case be the same or not?
 
No, it would not.
What if the small block is 1 m^3 and the large one is 100 m^3?
Assume you find the force you need to decrease the volume of the large one by 1 m^3.
Will the same force decrease the volume of the first one by 10m^3? Will any force be able to do this?

Can you see what kind of problems will arise trying to define a property in terms of absolute values? Not that is not possible.
Absolute value of volume change is not a property of the material but of the specific sample.
 
this is interesting! thanks.
 
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