Why does 1/[nlog(n+1)] diverge

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Homework Statement



Why does the series 1/[nlog(n+1)] diverge

Homework Equations


We know that 1/[nlog(n)] diverges by the integral test. However the question as written does not lend itself to be any integral precisely.


The Attempt at a Solution

 
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investigate the integral:

<br /> f(x) = \int_{1}^{x}{\frac{dt}{t \, \log{t}}}<br />

as x \rightarrow \infty.
 
Yes, however the integral doesn't work in this particular case
Note that the question says nlog(n+1), not nlogn
 
grossgermany said:
Yes, however the integral doesn't work in this particular case
Note that the question says nlog(n+1), not nlogn

1/((n+1)*log(n+1)) diverges, right? You can do an integral test or just notice it's the same series as 1/(n*log(n)) shifted one term. Now try and think of how to use a comparison test.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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