Why Does a Car Slide Downhill at a 45 Degree Incline Despite Equal Forces?

Click For Summary
SUMMARY

A car on a 45-degree incline will begin to slide due to the static coefficient of friction being equal to one, as demonstrated in the physics example discussed. The calculations confirm that the maximum static friction force equals the gravitational force acting parallel to the incline at this angle. Specifically, the equations derived show that at 45 degrees, the forces in both the X and Y directions balance out, but any additional force will initiate sliding. Thus, the assertion that the car will slide down is validated by the principles of static friction and gravitational force.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Familiarity with static and kinetic friction concepts
  • Basic trigonometry, particularly sine and cosine functions
  • Knowledge of force calculations involving mass and gravity
NEXT STEPS
  • Study the implications of static vs. kinetic friction in real-world applications
  • Explore advanced topics in physics, such as dynamics on inclined planes
  • Learn about the role of additional forces in motion, such as frictional forces in different materials
  • Investigate the effects of varying coefficients of friction on incline stability
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the mechanics of motion on inclined surfaces, particularly in relation to friction and gravitational forces.

MRGE
Messages
10
Reaction score
0
Ok, I was watching a physics lecture and there was an interesting example given

Heres the Example

"A rubber tire has a static coefficient of one, so at an angle of 45 degrees, the car will start to slide, which is independent of the area of the tires and mass of the car."

So i did the calculations real quick to see if this is true.

For the F (Friction Max) = Coefficient Friction x Normal Force

On an incline:
In the X direction, the Force can be measured in Mass(Gravity)Sin(Theta)
In the Y Direction, the force can be measured in Mass(Gravity)Cos(Theta)

(Correct me if i get any of this stuff wrong)


According to Newton's Law, The force that the car exerts on the ground, the ground as to exert an equal amount of force if the car has no acceleration in the y direction.

So: Mass(Gravity)Cos(Theta) Equals (=) Normal Force (Nf)

And at the Point of Breaking off toe Accelerate, the equation would be:

Mass(gravity)sin(Theta) - F(friction Max) = 0

Substitute F(friction Max) with (static friction = Ms)(Mass(gravity)Cos(Theta))


So you would get

Mass(gravity)sin(Theta) - Ms(M)gCos(theta) = 0

Deriving it from the equation, Than


Tan(theta) = Ms (Static Friction)

Than:

So I plugged Theta = 45 degrees
and 100 kg to those equations

F(Friction Max) = Mu x Normal Force

Tan(45)(100kg)(9.81m/s2)(Cos45) = 693.6717523

The Force in the X direction = (100kg)(9.81m/s2)Sin45 = 693.6717523 also

Since the forces are the same, how can the car move? The forces cancel each other out, granted a tiny force will able to make it slide down but if nothing touches is, the car will still be stationary. So, I can't quite figure out why the professor is saying the car will start to slide down at an angle of 45 degrees since both the Friction Max Force is equal to the X direction Force.

Anyone want to explain this for me?
 
Physics news on Phys.org
Seems to me you explained it yourself! Nice job, too.
Zero force holding it in place marks the point between sliding and not sliding, which you might call the beginning of the slide.
 

Similar threads

Replies
7
Views
2K
Replies
24
Views
3K
  • · Replies 5 ·
Replies
5
Views
7K
Replies
17
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
16
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
46
Views
7K
  • · Replies 5 ·
Replies
5
Views
2K