Why does a chemical compound precipitate metals differently than metal

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In a solution containing aqua regia or other acids, the addition of a powdered metal can precipitate all metals that are lower on the reactivity series, including both precious and base metals. In contrast, using specific chemical compounds like sodium metabisulfate or ammonium chloride results in the selective precipitation of particular metals, such as gold or platinum. This selectivity arises from the nature of the reactions involved; the powdered metal induces a redox reaction where electrons are transferred to any metal lower in reactivity, while the chemical compounds engage in metathesis or exchange reactions, targeting specific metals based on their chemical properties rather than reactivity alone. This distinction clarifies the mechanisms behind metal precipitation in these different scenarios.
BernieM
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In a solution of aqua regia (or other acids), if there is a precious metal dissolved, along with other metal ( such as other precious metals or base metals), and you add a powdered metal, you precipitate all the metals lower than it on the reactivity list.

If however, you use a chemical compound (such as sodium metabisulfate to precipitate gold or ammonium chloride for platinum), it predominantly only precipitates one particular metal.

Why is the compound selective?
 
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Your first example is redox chemistry and your precipitating M0 which was reduced by whatever reducing agent you added to your solution, the electrons don't care where they go as long as they are lower in energy and so on. Whereas in the second case you are doing a so-called Metathesis/Exchange Reaction and you are precipitating Ma|b|Ab|a|.
 
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I see my error now, thinking that it was all valence electron exchanges. Thanks.
 
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