Why does a hydrogen gas tube produce a hydrogen atomic spectrum?

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SUMMARY

The discussion centers on the production of the hydrogen atomic spectrum from hydrogen gas tubes, specifically the dissociation of H2 molecules into atomic hydrogen due to high voltage. The binding energy of the H2 molecule is 4.52 eV, while the excitation energy for the Balmer series requires at least 12 eV, indicating that the energy supplied is sufficient to dissociate the molecules. The continuous bombardment of energetic electrons leads to the emission of light from atomic hydrogen, resulting in observable spectra despite the initial presence of H2 molecules.

PREREQUISITES
  • Understanding of hydrogen molecular and atomic structures
  • Knowledge of binding energy concepts, specifically 4.52 eV for H2
  • Familiarity with the Balmer series and excitation energy requirements
  • Basic principles of quantum mechanics related to molecular dissociation
NEXT STEPS
  • Research the Balmer series and its excitation energy requirements in detail
  • Study the principles of molecular dissociation and recombination rates
  • Explore the Fulcher and Werner bands in relation to hydrogen emission
  • Investigate the transition from molecular hydrogen to plasma states in high-energy environments
USEFUL FOR

Physicists, chemists, and students studying atomic spectroscopy, particularly those interested in the behavior of hydrogen under high-energy conditions.

amilton
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To measure the atomic hydrogen spectrum people often uses hydrogen gas tubes as light source.
Since the gas in the tube is the molecule ##H_2## , why we obtain the spectrum of atomic hydrogen?
My guess is that because the voltage is so high, so that the molecules are totally dissociated.
If you could give me some reference I would be grateful.
 
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The H2 molecule has a binding energy of 4.52 eV. Visible spectra of H, the Balmer series, requires excitation to at least ##n=3##, which requires 12 eV from the ground state. The energy required for excitation is more than enough to break apart the molecule.
 
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DrClaude said:
The H2 molecule has a binding energy of 4.52 eV. Visible spectra of H, the Balmer series, requires excitation to at least n=3, which requires 12 eV from the ground state. The energy required for excitation is more than enough to break apart the molecule.
Is there any justification based on quantum mechanics that for higher energy the process of dissociation of hydrogen molecule is more probable than that of excitation of the electron of this molecule
 
In such a tube, you are not exciting one molecule once and looking at what happens, so the branching ratios between the different outcomes are not relevant.

The molecules end up continuous being hit by energetic electrons and quickly break apart, and you are left with atoms being hit by electrons and emitting light.
 
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DrClaude said:
In such a tube, you are not exciting one molecule once and looking at what happens, so the branching ratios between the different outcomes are not relevant.

The molecules end up continuous being hit by energetic electrons and quickly break apart, and you are left with atoms being hit by electrons and emitting light.
How do we know that the rate of dissociation is greater that of recombing (production of molecules)?
 
amilton said:
How do we know that the rate of dissociation is greater that of recombing

When you start out with 100% molecules there is only one direction the system can evolve in.
 
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Vanadium 50 said:
When you start out with 100% molecules there is only one direction the system can evolve in.
Also, you keep pouring energy in the system.
 
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if you keep pouring energy to the system we will arrive to a plasma state and so no spectrum
 
Hydrogen molecules do have emission bands. Such as Fulcher bands in visible and Werner bands in vacuum UV.
What determines the branching ratio between Balmer lines and Fulcher bands in visible, or Lyman lines and Werner bands in UV?
 
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amilton said:
if you keep pouring energy to the system we will arrive to a plasma state and so no spectrum

But we do see a spectrum.

More to the point, we see emission lines, so clearly energy is leaving the system through at least that one process.
 

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