Arkuski
- 38
- 0
Suppose that f is bounded by M. Prove that ω(f^2,[a,b])≤2Mω(f,[a,b]).
I can show that ω(f,[a,b])≤2M and that ω(f^2,[a,b])≤M^2 but this procedure is getting me nowhere. I also have a similar problem that likely calls for the same approach:
Suppose that f is bounded below by m and that m is a positive number. Prove that ω(1/f,[a,b])≤ω(f,[a,b])/m^2.
This one I think I have right but my instructor is telling me that it's wrong. Since all values are positive, by the nature of \frac{1}{x}, \displaystyle\sup f = \frac{1}{\displaystyle\inf f} and \displaystyle\inf f = \frac{1}{\displaystyle\sup f}. We can now analyze the oscillation as follows:
ω(1/f,[a,b])=\frac{1}{\displaystyle\inf f}-\frac{1}{\displaystyle\sup f}=\frac{ω(f,[a,b])}{(\displaystyle\inf f)(\displaystyle\sup f)}≤\frac{ω(f,[a,b])}{m^2}
I can show that ω(f,[a,b])≤2M and that ω(f^2,[a,b])≤M^2 but this procedure is getting me nowhere. I also have a similar problem that likely calls for the same approach:
Suppose that f is bounded below by m and that m is a positive number. Prove that ω(1/f,[a,b])≤ω(f,[a,b])/m^2.
This one I think I have right but my instructor is telling me that it's wrong. Since all values are positive, by the nature of \frac{1}{x}, \displaystyle\sup f = \frac{1}{\displaystyle\inf f} and \displaystyle\inf f = \frac{1}{\displaystyle\sup f}. We can now analyze the oscillation as follows:
ω(1/f,[a,b])=\frac{1}{\displaystyle\inf f}-\frac{1}{\displaystyle\sup f}=\frac{ω(f,[a,b])}{(\displaystyle\inf f)(\displaystyle\sup f)}≤\frac{ω(f,[a,b])}{m^2}