Why does Coulomb's Law include a pi in the denominator?

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The discussion revolves around a student's confusion regarding the presence of pi in the denominator when calculating the electric field from a uniform infinite line charge using Coulomb's Law, compared to the result from Gauss' Law. The student initially believes there is a discrepancy between the two methods, as Gauss' Law yields a simpler denominator. Upon further examination and detailing their steps, the student identifies a mistake in their integration process, resolving the issue. This highlights the importance of carefully reviewing calculations and the common experience of discovering errors through explanation. The conversation emphasizes problem-solving techniques in physics, particularly in electrostatics.
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Homework Statement


I'm sure I'm missing something simple here, but to the point:

I calculate the electric field a distance r from a uniform straight infinite line charge using Gauss' Law and get an answer; I do the same calculation using Coulomb's law and get the same answer but a pi remains in the denominator (that was not there in the Gauss' Law solution). I don't know how to enter the equation here, but in both answers the numerator is the linear charge density. The Gauss' Law denonminator is 2r times epsilon; Coulomb's law denominator is 2(pi)r times epsilon. Help!


Homework Equations


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The Attempt at a Solution


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Can you write out each of your steps? Maybe then one of us'll be able to spot the error.
 
Well, thanks for the fast response. In writing out the steps as you requested I caught a (dumb) integration error - I'm straight now. Thanks.
 
Old Guy said:
Well, thanks for the fast response. In writing out the steps as you requested I caught a (dumb) integration error - I'm straight now. Thanks.

You can't imagine how many times I've been stumped on a problem only to realize my error while explaining what I did to someone. :)
 
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