Why Does Enthalpy of Saturated Vapour Increase with Temperature?

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The enthalpy of saturated vapor increases with temperature due to higher internal energy and increased pressure-volume work (PV). As temperature rises, both internal energy and PV terms contribute to this increase. However, this trend does not hold at all temperatures; while the enthalpy of saturated liquids consistently rises with temperature, the heat of vaporization decreases near the critical point. Consequently, as one approaches the critical point, the enthalpy of saturated vapor can actually decrease with temperature. Understanding these dynamics is essential for accurate thermodynamic analysis.
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Homework Statement



I have the ammonia liquid-vapour tables and I have noticed that the enthalpy of a saturated vapour increases as temperature increases. Can someone please help me to understand why this is the case?

Homework Equations



H = U + pV

The Attempt at a Solution



I assume that at higher temperatures the vapour will have a greater internal energy. Is this why enthalpy increases with temperature?

Thanks!
 
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r.physics said:

Homework Statement



I have the ammonia liquid-vapour tables and I have noticed that the enthalpy of a saturated vapour increases as temperature increases. Can someone please help me to understand why this is the case?

Homework Equations



H = U + pV

The Attempt at a Solution



I assume that at higher temperatures the vapour will have a greater internal energy. Is this why enthalpy increases with temperature?

Thanks!
It also has a higher PV, since PV=nRT. So, both U and PV are higher.

Also, this is not the case at all temperatures. The enthalpy of the saturated liquid always increases with temperature, but the heat of vaporization decreases as the critical point is approached. So, at temperatures and pressures approaching the critical, the enthalpy of the saturated vapor actually decreases with temperature (i.e., along the saturation line).
 
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