Why does length contraction not cause Black holes?

Justice Hunter
Messages
98
Reaction score
7
So i was watching this video :



And it got me thinking... i began wondering why, when space contracts from someones frame of reference (In the video, this would be the frame of reference of the cat), why is it that the protons don't become black-holes when the space contracts?

If the density change has an effect on the electro-magnetic force, why would it not have any gravitational effects?

It seems to be contradictory, since from the reference frame of someone stationary, looking at the cat, there is no change in density of the protons in the wire, but instead, we see the cat contract. and we don't see things becoming black holes when moving at or near the speed of light, so i assume that the protons in the wire do not becomes black holes either.

So what is the reason length contraction doesn't create black holes in any reference frame?
 
Physics news on Phys.org
Length contraction arises because of the relativity of simultanity. So it's not because space itself contracts, but because every observer has it's own notion of 'simultanity', and because spatial length is defined via simultanious events one observes length contraction. The observed object itself doesn't care less about those observers.
 
  • Like
Likes Justice Hunter
Justice Hunter said:
why is it that the protons don't become black-holes when the space contracts?

Because whether or not something is a black hole is not frame-dependent. The spacetime curvature an object produces is not due to its "density", which is frame-dependent; it is due to the object's stress-energy tensor, which is covariant. So an object's spacetime curvature doesn't change when you change frames.

Justice Hunter said:
If the density change has an effect on the electro-magnetic force, why would it not have any gravitational effects?

It's not the density change that affects the electromagnetic force; it's relative motion between the source and the object the source is acting on. Also, force is not the same as the source of the force. The EM force between a proton and an electron at rest relative to the proton will be different from the EM force between a proton and an electron moving past the proton at high speed. But the charge on the proton (the ultimate source of its EM force) does not change.

Similarly, the gravitational force between a massive body and an object at rest relative to it is different from the gravitational force between the same body and an object moving past it at high speed. But the body's mass, or more precisely its stress-energy tensor (the ultimate source of its gravitational force), does not change.
 
  • Like
Likes Justice Hunter
Thanks guys i understand now i think!
 
Thread 'Can this experiment break Lorentz symmetry?'
1. The Big Idea: According to Einstein’s relativity, all motion is relative. You can’t tell if you’re moving at a constant velocity without looking outside. But what if there is a universal “rest frame” (like the old idea of the “ether”)? This experiment tries to find out by looking for tiny, directional differences in how objects move inside a sealed box. 2. How It Works: The Two-Stage Process Imagine a perfectly isolated spacecraft (our lab) moving through space at some unknown speed V...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. The Relativator was sold by (as printed) Atomic Laboratories, Inc. 3086 Claremont Ave, Berkeley 5, California , which seems to be a division of Cenco Instruments (Central Scientific Company)... Source: https://www.physicsforums.com/insights/relativator-circular-slide-rule-simulated-with-desmos/ by @robphy
Does the speed of light change in a gravitational field depending on whether the direction of travel is parallel to the field, or perpendicular to the field? And is it the same in both directions at each orientation? This question could be answered experimentally to some degree of accuracy. Experiment design: Place two identical clocks A and B on the circumference of a wheel at opposite ends of the diameter of length L. The wheel is positioned upright, i.e., perpendicular to the ground...

Similar threads

Replies
10
Views
2K
Replies
7
Views
2K
Replies
22
Views
1K
Replies
14
Views
2K
Replies
45
Views
5K
Replies
54
Views
3K
Replies
4
Views
2K
Back
Top