Why Does Lenz's Law Induce a Clockwise Current When a Bar Moves Right?

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Lenz's Law indicates that the induced current in a conductor opposes the change that produced it, resulting in a clockwise current when a bar moves to the right in a magnetic field directed out of the page. The right-hand rule confirms this direction of current flow. If the bar were to move to the left, the induced current would reverse to a counter-clockwise direction. The discussion also touches on the relationship between magnetic force on charges and induced current, emphasizing the need for clarity in understanding the direction of the induced magnetic field. Overall, the explanation seeks to deepen the understanding of how motion in a magnetic field influences current direction.
Misscynical
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The bar in figure Q31.5 moves on rails to the right with a velocity, v, and the uniform, constant magnetic field is directed out of the page. Why is the induced current clockwise? If the bar were moving to the left, what would be the direction of the induced current?
(The figure is at the bottom of page 24 in the document linked below)

My answer is;
As Lenz's law states that the induced current in a conductor acts in the direction that opposes the charge that produced it. Consequently, the magnetic field is acting into the page, meaning that the induced current is clockwise (by the right hand rule).
If the bar was moving to the left, the induced current would be counter-clockwise.

If this correct?

Thank you for any help =)

http://www.electron.rmutphysics.com...-Serway-Beichne 6edr-4/31 - Faraday's Law.pdf
 
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For a moving conductor in a magnetic field can't you just use that the force on a charge q is F = q*VXB and this force causes a current?
 
Misscynical said:
My answer is;
As Lenz's law states that the induced current in a conductor acts in the direction that opposes the charge that produced it. Consequently, the magnetic field is acting into the page, meaning that the induced current is clockwise (by the right hand rule).
If the bar was moving to the left, the induced current would be counter-clockwise.

If this correct?
The picture didn't load here when I clicked on the link, but I can imagine what it was.

You kind of just assert what the answer is. Can you explain in a bit more detail how you know the induced field points into the page?
 
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