Why Does My Fourier Transform Magnitude Plot Look Incorrect?

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SUMMARY

The forum discussion centers on an issue with Fourier analysis using Mathematica, specifically regarding the magnitude plot of the Fourier Transform of the function s(t) = (1/(4*(Pi*t)^(3/2))) * Exp[-3/(4*t)]. The user expected a low-pass filter response, characterized by high initial amplitude that decreases with frequency, but the output did not match this expectation. The discussion suggests that the user may have misunderstood the nature of the function or the output from Mathematica, which is likely accurate.

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This discussion is beneficial for signal processing engineers, data analysts, and anyone working with Fourier analysis in Mathematica who seeks to understand the characteristics of frequency response and magnitude plots.

Oliver2000
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Hallo all,

i have a problem with Fourier analysis and i really hope yoou can help me in this forum. i have been trying to find the reason for my problem since many weeks but i could not.

Well, i have this Equation:s(t) = (1/(4*(Pi*t)^(3/2))) * Exp[-3)/(4*t)]

and i need to find the Fourier Frequency for this funtion and then find the magnitude.
my solution:
i used the software mathematica to do it, so i could plot the function s(t) and then its magnitude using as it is shown in the attached images:

Plot[FourierTransform[(1/(4*(Pi*t)^(3/2)))*Exp[-(3)/(4*t)], t,f] // Abs, {f, 0, 100}]

but the problem that the plot of magnitude should look different. it should look like lowpass filter. i mean, that the frequencies should have high amplitude at the beginning and then they should have lower and lower amplitude.
or maybe i have made something wrong in mathematica which led to this weird result. i hope u can help me
regards
 

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What makes you so sure that this is a low pass filter? I see no reason to think that it is. Quite likely Mathematica has simply given you a correct result that did not match your preconception.
 

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