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Why does my friend say I am wrong?

  1. May 5, 2012 #1
    A special fastener is used to anchor three cables to an east-facing wall in a factory. One cable applies a load of 300N straight down. The second cable applies a load of 400N, horizontally toward the south. The third cable applies a load of 500N toward the north, but angled at 30 degrees from the horizontal , down toward the floor. What is the total load on the fastener?

    my solution
    the vertical component of the 500N force = 500*sin30 = 250 N down
    the north component of the 500 N force = 500*cos30 north

    the sum of the north-south components = 300 north + 500*cos30 north + 400 south
    Net north-south component = 300 + 500*cos30 - 400 = 333 N

    The 333 N force vector and the 250 N force vector are perpendicular to each other. The vector that represents the sum of these 2 vectors is the hypotenuse of the right triangle formed by the 3 vectors.
    Magnitude of total force = (250^2 + 333^2)^0.5 = 416 N
     
  2. jcsd
  3. May 5, 2012 #2

    I like Serena

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    Hi davedave,

    Your reasoning is sound.
    But... what happened to the load of 300 N straight down?
    You appear to have counted this force as being northward.
     
  4. May 5, 2012 #3

    tiny-tim

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    hi davedave! :smile:

    the 300 N is down

    how do you get a north/south component? :confused:
     
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