Why Does My Quadratic Equation Look Incorrect?

AI Thread Summary
The discussion revolves around a misunderstanding of the equation transformation from 300 = (x+3)(x+2) into standard form. Participants clarify that the term "Stanford form" is incorrect, and the proper term is "standard form." The original equation and its rewritten form are confirmed to be correct, but the issue lies in the expression for the box's dimensions. Specifically, the width should be defined as W = x - 2 instead of the initially provided expression. This clarification addresses the confusion regarding the transformation of the quadratic equation.
SunnyBoy123
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Ok so what am I doing wrong, when i try to put equation 300 = (x+3)(x+2)(1) into Stanford form I get x^2 + 5x - 294 = 0.

http://imgur.com/a/N9E83
 
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SunnyBoy123 said:
Ok so what am I doing wrong, when i try to put equation 300 = (x+3)(x+2)(1) into Stanford form I get x^2 + 5x - 294 = 0.

http://imgur.com/a/N9E83

There is no such thing as a "Stanford form", but there can be a "standard form". Anyway, you have re-written the equation correctly.
 
The equation that you have correctly re-written is wrong.
 
lewando said:
The equation that you have correctly re-written is wrong.

This is probably very confusing to the OP. You are literally saying that the equation ##(x+2)(x+3) = 300## is wrong, because that is the equation he re-wrote. In fact, the equation is correct and his re-write of it is also correct; the book's re-write is wrong.
 
Last edited:
lewando said:
The equation that you have correctly re-written is wrong.
Sorry--upon re-read this is unclear. My intent was to encourage him to look upstream a bit more.
 
SunnyBoy123 said:
Ok so what am I doing wrong, when i try to put equation 300 = (x+3)(x+2) (1) into Stanford standard form I get x^2 + 5x - 294 = 0.
The two equations you have above are equivalent.

The problem is with the expression given for the width of the box. The length and width of the box are each 2 inches less than the length and width of the metal sheet, respectively.

So the width of the box should have been given as ##\ W=x-2\ ##.

d4Fv4vQ.jpg
 
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