Why Does My Satellite Orbit Calculation Not Match the Expected 1.8 Hour Period?

Thread starter smw1016
Start date Oct 22, 2008
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Orbit Satellite

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To achieve a 1.8-hour orbital period, the altitude calculation for a satellite must be precise. The formula used, r = (GMT^2/4π^2)^(1/3) - Earth's radius, is generally correct, but unit consistency is crucial. Ensure all measurements are in meters, seconds, and kilograms to avoid discrepancies. Incorrect unit conversions can lead to significant errors in the calculated altitude. Accurate calculations are essential for determining the correct satellite orbit.

Oct 22, 2008

smw1016

At what altitude will a satellite complete a circular orbit of the Earth in 1.8 hours?

i used r=(GMT^2/4pi^2)^1/3 -Radius of the earth.

but I am keep getting wrong answer please help

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Oct 22, 2008

Redbelly98

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I think that equation is correct. You may want to double-check the units: is everything in terms of m, s, and kg? (I.e., not km for example.)

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