Why Does (n 0) Equal 1 in Combinatorics?

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In combinatorics, the expression (n 0) equals 1 because it represents the number of ways to choose 0 elements from a set of n elements, which is always one way—by choosing nothing. This is defined using binomial coefficients, expressed mathematically as \binom{n}{k}=\frac{n!}{k!(n-k)!}. The confusion often arises because this notation is not commonly used in high school math curricula. The convention that 0! equals 1 is crucial to understanding this concept. Overall, the topic highlights the importance of binomial coefficients in combinatorial mathematics.
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2cct0d5.png


in the above pic, (n 0) = 1?? what topic in math is that? i never saw this in my high school math and only saw it in my uni class. i don't know how that is. can someone please help me?
 
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They are binomial coefficients. We define

\binom{n}{k}=\frac{n!}{k! (n-k)!}

You have no doubt seen this before in combinatorics, but with other notation. It is a mystery to me why high school textbooks don't use the \binom{n}{k} notation.

http://en.wikipedia.org/wiki/Binomial_coefficient
 
super! and of course i know about binomial coefficients. just like this
cf53c9e57be2cdfe572da491e078d9ff.png


thank you very much. now I'm not scared anymore! :D
 
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