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my question is short simply why reversibility requires equilibrium?
The discussion centers around the relationship between reversibility and equilibrium in thermodynamic processes. Participants explore the conditions under which processes can be considered reversible and the implications of irreversibility, particularly in the context of statistical mechanics.
The discussion does not reach a consensus on the relationship between reversibility and equilibrium. Multiple viewpoints are presented, particularly regarding the nature of irreversible processes and the need for equilibrium.
Participants reference concepts such as entropy generation and finite rates of transport, but there are no detailed mathematical steps or definitions provided. The discussion appears to depend on participants' varying levels of familiarity with statistical mechanics and thermodynamic principles.
This discussion may be of interest to students and researchers in physics and engineering, particularly those studying thermodynamics and statistical mechanics.
I was studying mehran kerdarbook on statistical mechanics of particlesberkeman said:What research have you done about this question? Can you post links to your reading that led to this question? Thanks.
Where can I learn about boltzmann's H theorem?Chestermiller said:In irreversible processes, transport of mass, momentum and heat occur at finite rates, and these cannot be reversed for the system without also bringing about a net change in the surroundings. Mass transfer involves diffusion at finite rates. Momentum transfer involves viscous dissipation of mechanical energy to internal energy and involves finite viscous stresses at finite deformation rates. Heat Transfer involves heat conduction at finite temperature gradients. All of these involve entropy generation within the system, rather than entropy transport via heat flow across the boundary of the system.