Why does sound reflect and create an echo in certain conditions?

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Sound intensity increases at night due to denser air, which enhances sound transmission influenced by factors like humidity and temperature. Diffraction of sound is more noticeable than that of light primarily because sound waves have longer wavelengths. Sound reflects off surfaces regardless of distance, but an echo is only heard under specific conditions related to that distance. The ability to perceive an echo depends on the time it takes for the reflected sound to return to the listener. Understanding these principles clarifies the relationship between sound reflection and echo formation.
Misr
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1-why does sound intensity increase at night?
2-what makes diffraction of sound more observable than diffraction of light?
3-reflection of sound takes place when it falls on a reflecting surface whatever the distance between the vibrating source and the surface
but in case of echo there are certain conditions to be heard,,,so am I understanding this in the right way??
 
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Misr said:
1-why does sound intensity increase at night?

This depends or air density, humidity, temperature and wind direction. Denser air transmits sound better. Generally night air is usually denser then day air, so sound usually carries better at night.

2-what makes diffraction of sound more observable than diffraction of light?
Wavelength.
3-reflection of sound takes place when it falls on a reflecting surface whatever the distance between the vibrating source and the surface
but in case of echo there are certain conditions to be heard,,,so am I understanding this in the right way??

Please rephrase question 3.
 
Denser air transmits sound better. Generally night air is usually denser then day air, so sound usually carries better at night.
what makes denser air transmit sound better?

Wavelength
I know.but how?if the wavelength of a sound wave is bigger so what makes this observable?

Please rephrase question 3.
I mean, echo is a result of sound reflection...but sound can reflect also without making an echo (depends upon the distance between the vibrating source and the reflecting surface)
hope it's clear now
Thanks very much for your help
 
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