Why Does Steepness in a Potential Energy Graph Indicate Greater Force?

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The discussion centers on how steepness in a potential energy graph correlates with the magnitude of force acting on a particle. Participants debate which regions (Q, W, T) exhibit the greatest force, with one argument favoring region W due to its higher potential energy when considering repulsive forces. Conversely, another viewpoint suggests region T has the greatest magnitude based on its position on the graph, particularly for attractive forces. The ambiguity in the problem statement regarding whether the force is repulsive or attractive complicates the determination of the correct answer. Ultimately, the lack of clarity in the force type prevents a definitive conclusion.
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A plot of a graph describes the potential energy of a particle, due to the force exerted on it by another particle, as a function of distance. At which three regions (Q), (W), (T) would the magnitude of force on the particle be the greatest? and why?

[T]
(T) is suppose to be located the most (=) on the x axis





-(0)----------------[Q]---------------------------…


[W]

The answer Is (W)
Why?

I answered (T) because I thought it had the greatest magnitude and being the farthest (+) value on both the y and x axis
 
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If the force is repulsive, as in like charges, then potential decreases with distance, and W would have the highest potential. If the force is attractive, as in gravity or opposing charges, potential increases with distance, and T would have the highest potential.

The problem statement doesn't specify if the force is repulsive or attractive, so it really can't be asnwered as worded.
 
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