Why Does the Chain Rule Apply Differently to the Derivative of (x^2+x)^(1/2)?

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The discussion focuses on the application of the chain rule in calculus, specifically for the function D = (x^2 + x)^(1/2). The correct derivative is derived as D' = (1/2)(x^2 + x)^(-1/2)(2x + 1)(x'), which emphasizes the proper use of the chain rule. The confusion arises from incorrectly applying the chain rule by substituting 2x' instead of x' in the derivative calculation. This highlights the importance of correctly identifying the inner function when differentiating composite functions.

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D= (x^2+x)^(1/2)

Why does the chain rule in this case produce D' = (1/2)(x^2+x)^(-1/2) (2x+1)(x')

and not D' = (1/2)(x^2+x)^(-1/2) (2x+1)(2x')
 
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[tex]\frac{dD}{dt}=\frac{dx}{dt} \times \frac{dD}{dx}[/tex]

So like in the other thread, can you understand why now?
 

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