Why Does the Derivative of 2 + tan(x/2) Include a .5 Term?

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SUMMARY

The derivative of the function 2 + tan(x/2) is calculated as 0 + sec^2(x/2) * (1/2), resulting in 0.5 + sec^2(x/2). The constant term 2 contributes a derivative of 0, while the chain rule is applied to the tan(x/2) term, leading to the inclusion of the 0.5 factor from the derivative of x/2. This demonstrates the importance of the chain rule in differentiation.

PREREQUISITES
  • Understanding of basic calculus concepts, particularly differentiation.
  • Familiarity with the chain rule in calculus.
  • Knowledge of trigonometric functions and their derivatives.
  • Ability to manipulate algebraic expressions involving derivatives.
NEXT STEPS
  • Study the chain rule in more depth, focusing on its applications in calculus.
  • Learn about the derivatives of trigonometric functions, specifically tan(x).
  • Explore examples of differentiating composite functions.
  • Practice solving derivative problems involving constants and trigonometric functions.
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Students studying calculus, particularly those learning about differentiation and the chain rule, as well as educators seeking to clarify these concepts.

bobsmith76
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I understand everything except why the derivative of 2 + tan (x/2) is .5 + sec^2(x/2)
I don't understand the .5 part. I understand the sec part. I would think the derivative of 2 would be C, or just disappear.
 
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never mind. I got it. I've got to use the chain rule. the derivative of t/2 is 1/2
 

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