taffer33
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Concrete for example - you need less concrete to obtain the same lead equivalent for photon energy 500 keV than for 200 keV. What is the reason for this?
The discussion revolves around the effectiveness of low-Z (low atomic number) materials, specifically concrete, as shielding against photon radiation at varying energy levels. Participants explore the reasons behind the differing shielding requirements for photon energies of 200 keV and 500 keV, focusing on interactions such as the Compton Effect and the properties of materials like lead and concrete.
Participants express differing views on the reasons behind the effectiveness of low-Z shielding at different photon energies, with no consensus reached on the underlying mechanisms or the implications of the data presented.
Participants reference specific articles and data sources to support their claims, but the discussion includes unresolved questions about the calculations and the implications of the mass attenuation coefficients.
It's a property of lead rather than a property of the concrete.taffer33 said:https://archive.org/details/jresv38n6p665
it's in this article for example
I asked this question as I was reading about shieldings in PET departments, where they suggest lead/concrete ratio 12-15, while ratio for 150 keV X-Ray is 80... (These are example regulations from my country).